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STatiana [176]
2 years ago
15

How many electrons should be in an atom’s valence shell (with the exception of hydrogen and helium) to become stable? 2 4 6 8.

Physics
1 answer:
podryga [215]2 years ago
4 0

Answer:

8

Explanation:

octet rule: Atoms lose, gain, or share electrons in order to have a full valence shell of eight electrons. Hydrogen is an exception because it can hold a maximum of two electrons in its valence level.

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PLZ ANSWER ASAP!!!!!!!
jenyasd209 [6]

Explanation:

It is given that,

Mass of platinum bar, m = 750 g

Length of the bar, l = 5 cm

Breadth of the bar, b = 4 cm

Width of the bar, h = 1.5 cm

Volume of the bar, V=l\times b\times h

V=5\times 4\times 1.5=30\ cm^3

We need to find the density of the platinum bar. The density of any substance is given by :

d=\dfrac{m}{V}

d=\dfrac{750\ g}{30\ cm^3}

d=25\ g/cm^3

So, the density of the platinum bar 25\ g/cm^3. Hence, this is the required solution.

4 0
3 years ago
How does the sun provide us with the energy we need to run our bodies?
ivanzaharov [21]
The sun radiates a lot of things we need like vitamin D and heat. It also is the energy source of organisms that survive off of photosynthesis, like plants, which we or other consumers eat.
It's like this:
Sun--->Producers (Plants and Protists) ---> Consumers (animals and humans) ---> Decomposers (mostly bugs, bacteria, and fungi)
6 0
3 years ago
Read 2 more answers
What mode of transportation uses sliding friction
Sonja [21]
A mode that uses sliding friction would be sledding. :) 


8 0
4 years ago
A plane is traveling at a velocity of 90 m/s. It accelerates at a constant rate of 1.5 m/s​2 until its velocity reaches 500 m/s.
katrin2010 [14]

Answer:

The distance the plane covered while it was accelerating is 80,633.3 m

Explanation:

Given;

initial velocity of the plane, u = 90 m/s

acceleration of the plane, a = 1.5 m/s²

final velocity of the plane, v = 500 m/s

The distance covered by the plane is given as;

v² = u² + 2ad

where;

d is the distance covered by the plane;

500² = 90² + 2(1.5)d

500²  - 90² = 3d

241900 = 3d

d = 241900 / 3

d = 80,633.3 m

Therefore, the distance the plane covered while it was accelerating is 80,633.3 m

5 0
3 years ago
A He–Ne laser illuminates a narrow, single slit that is 1850 nm wide. The first dark fringe is found at an angle of 20.0∘ from t
egoroff_w [7]

Answer:

Wavelength of light will be 632.73 nm

Explanation:

We have given width of the single slit d=1850nm-1850\times 10^{-9}m

Angle is given as \Theta =20^{\circ}

We have to find the wavelength of light for first dark fringe

We know that for dark fringe it is given that

dsin\Theta =n\lambda

For first fringe n = 1

So 1850\times 10^{-9}\times sin20^{\circ} =1\times \lambda

\lambda =632.73nm

3 0
3 years ago
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