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3 years ago

A car traveling at 34 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds. What is its acceleration?

1 answer:

swat323 years ago

3 0

The acceleration of the object described above is calculated by dividing the given initial velocity by the time it took for it to completely stop. That is,

a = Vi / t

Substituting the known values,

a = (34 m/s) / 6 s = 5.67 m/s²

The answer to this item is -5.67 m/s² because the motion of the object is that it is coming to a full stop from high velocity motion.

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The riddle is solved by knowing that there is only one person left in the garden and that is you.

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2 years ago

A. Telephone signals are often transmitted over long distances by microwaves. What is the frequency of microwave radiation with

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(a) 10 GHz is the frequency of microwave radiation.

(b) 0.167 ms is required by the microwave to travel between two mountains.

Answer:

Explanation:

(a). 1 MHz is the frequency of microwave radiation.

(b) 0.167 ms is required by the microwave to travel between two mountains.

Answer:

Explanation:

a. Frequency is the measure of number of times a same thing will be repeated in a given time interval for a given time. And wavelength is the measure of distance between two successive crests or troughs. So wavelength and frequency are inversely proportional to each other. And velocity of light is the proportionality constant.

So frequency of microwave radiation = Speed of light/Wavelength of radiation

Frequency = $\frac{3*10^{8} }{3*10^{-2} }$

Frequency = $10^{8+2} = 10^{10}=10 GHz$

So 10 GHz is the frequency of microwave radiation.

b). As microwave is a part of light waves, so it will be experiencing the speed of light.

As the speed is 3* $10^{8}$ m/s and the distance between the two mountains is given as 50 km, then time can be calculated as

Time = Distance/Velocity

Time = $\frac{50*10^{3} m}{3*10^{8} }=16.67*10^{3-8}=16.67*10^{-5}$

So time = 0.167 ms.

Thus, 0.167 ms is required by the microwave to travel between two mountains.

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