Answer:
f1 = 58.3Hz, f2 = 175Hz, f3 = 291.6Hz
Explanation:
lets assume speed of sound is 350 m/s.
frequencies of a standing wave modes of an open-close tube of length L
fm = m(v/4L)
where m is 1,3,5,7......
and fm = mf1
where f1 = fundamental frequency
so therefore: f1 = 350 x 4 / 1.5
f1 = 58.3Hz
f2 = 3 x 58.3
f2 = 175Hz
f3 = 5 x 58.3
f3 = 291.6Hz
Answer:
You are moving away from him at 90% the speed of light. Joan is moving away from him at as speed that is faster than 90% of the speed of light but slower than the whole speed of light.
Explanation:
According to relativity, you cannot exceed the speed of light.
Either a or b
not exactly sure which
