There is one mistake in the question as unit of height of building is not given.So I assume it as meter.The complete question is here
You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 m tall, is walking alongside the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor’s head, where should the professor be when you release the egg? Assume that the egg is in free fall.
Answer:
d=3.67 m
Explanation:
Height of building=46.0 m
First we need to find time taken by egg to reach 1.80 m above the surface
So to find time use below equation
As velocity 1.20m/s is given and we have find time.So we can easily find the distance
So
Answer:
Explanation:
Magnetic field due to a moving charge
B = μ₀ / 4π x (qv x r)/r²
Given
B = .3 X 10⁻⁶ T,
r = 60 x 10⁻³ m
Putting these values in the given equation
.3 x 10⁻⁶ = 10⁻⁷ x qvsinθ /( 60 x 10⁻³)²
θ = 90 °
qv = 10.8 x 10⁻³
At point P
Sinθ = 60 / 72
r² = 72 x 72 x 10⁻⁶
B = 
= 0.17 μT
It would be d and c hoped i helped!
Answer:
139.6m/s
Explanation:
Calculate the tension first, T=m*g
mass(m): 1750kg, gravity(g): 9.8m/s^2
T= 1750*9.8
=17150N
Then calculate the wave speed using the equation v = √ (T/μ)
v= √(17150N)/(0.88kg/m)
=139.6m/s
Henry's Law (formulated in 1803 by William Henry) states that aa constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid.
Mathematically it can be formulated as
C = H⨯P
being:
C: the molar concentration of dissolved gas A,
P: the partial pressure of it
H: Henry's constant
Substituting:
C = P * H
C = (2.50 * 0.9869) * 58.0
C = 143.1
Answer:
the solubility (in m units) is
C = 143.1
