Question

200.0 mL of a 0.845 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution?

Answer 1

• M be molar concentration
• V be volume

So

• M1=0.845M
• V1=200mL=0.2L
• V2=0.6L
• M2=?

$\\ \tt\rightarrowtail M1V1=M2V2$

$\\ \tt\rightarrowtail 0.845(0.2)=0.6M2$

$\\ \tt\rightarrowtail 0.169=0.6M2$

$\\ \tt\rightarrowtail M2=0.281M$