200.0 mL of a 0.845 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution?

Chemistry

1 answer:

Ipatiy [6.2K]2 years ago

7 0

M be molar concentration
V be volume

M1=0.845M
V1=200mL=0.2L
V2=0.6L
M2=?

$\\ \tt\rightarrowtail M1V1=M2V2$

$\\ \tt\rightarrowtail 0.845(0.2)=0.6M2$

$\\ \tt\rightarrowtail 0.169=0.6M2$

$\\ \tt\rightarrowtail M2=0.281M$

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