The name of CuO is Copper(II) oxide have the two most common oxidation states of copper are +2 and +1.
<h3>What is copper oxide used for?</h3>
Copper oxide is a trace element for the zootechnical and agricultural sector. Cupric oxide is also used as a raw material for the production of catalysts and pigments in the field of ceramics, glass and plastics.
This compound makes two different types of bonds being the hydrogen bond when it's a hydrogen and covalent bond when we have an oxygen or a nitrogen.
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Answer:
16.92 g C13H18O2
Explanation:
If the molecular mass of C13H18O2 is 206.3 amu, then molar mass of C13H18O2 is 206. 3 g/mol.
So, if we have 0.082 mol C13H18O2, than it is
206.3 g/mol*0.082 mol = 16.92 g C13H18O2.
A titration is defined as 'the process of determining the quantity of a substance A by adding measured increments of substance B, the titrant, with which it reacts until exact chemical equivalence is achieved (the equivalence point)'.
The Molarity of the HCl Solution requires the addition of 24.6 mL of titrant is 0.0836 M (to 3 significant figures)
<h3>What is Titrant?</h3>
A reagent solution of precisely known concentration that is added in titration
Given reaction HCl + NaOH ===> NaCl +
neutralization reaction
Note that the mole ratio is 1:1 meaning that 1 mole HCl reacts with 1 mole NaOH to produce 1 mole NaCl and 1 mole 
Find moles of NaOH used:
18.45 ml x 1 L/1000 ml x 0.085 mol/L = 0.002091 moles NaOH used
This meant that there must be 0.002091 moles of HCl present in the 25.0 mls.
We want to find the molarity (M) which is moles HCl/liter of solution. We know the moles, and we also know the liters of solution (25.0 mls x 1 L / 1000 mls = 0.025 liters)
M = 0.002091 moles HCl / 0.025 liters = 0.08364 M = 0.0836 M (to 3 significant figures)
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Answer:
Final volume v2 = 0 ml
Explanation:
Given:
Initial temperature = 100°C
Initial volume = 75 ml
Final temperature = 0°C
Find:
Final volume
Computation:
Using Charles law formula;
⇒ V1 / T1 = V2 / T2
Where
⇒ Initial temperature = T1
⇒ Initial volume = V1
⇒ Final temperature = T2
⇒ Final volume = V2
So,
⇒ 75 / 100 = V2 / 0
Final volume v2 = 0 ml