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Setler [38]
2 years ago
8

Molecules can exist as: A)solids B) liquids C) gases D) all of the above

Chemistry
1 answer:
DerKrebs [107]2 years ago
6 0

I believe it is D. Hope this helps you!

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DedPeter [7]
Suuurre...

If you want to die!!


3 0
3 years ago
What would be the oxidation and reduction half reactions for this equation?
Sedbober [7]

Answer:

Fe(s) → Fe²⁺(aq) + 2e⁻   OXIDATION

Mg²⁺(aq) + 2e⁻ → Mg(s)   REDUCTION

Explanation:

The redox reaction is: MgCl₂(aq) + Fe(s) → FeCl₂(aq) + Mg(s)

We need to know that elements in ground state have 0 as the oxidation state.

Iron in the reactants, and Mg in the products

In the magnessium chloride, the Mg acts with+2, so the oxidation state has decreased → REDUCTION

In the iron(II) chloride, the Fe acts with +2, so the oxidation statehas increased → OXIDATION

The half reactions are:

Fe(s) → Fe²⁺(aq) + 2e⁻   OXIDATION

Mg²⁺(aq) + 2e⁻ → Mg(s)   REDUCTION

5 0
3 years ago
How many grams of H2O would be produced if you started with 7 moles of ethylene (C2H4 )?
nydimaria [60]

Answer:

Explanation:

so if the reaction is C2H4+3O2-->2H2O+2CO2

if there were 7 moles of C2H4:

(see the attachment)

4 0
2 years ago
Calculate the values of ΔU, ΔH, and ΔS for the following process:
ladessa [460]

Answer:

ΔU = 45.814 KJ

ΔH = 46.4375 KJ

ΔS = 18.76 J/K

Explanation:

            H2O(l)        →          H2O(l)                →              H2O(steam)

   298.15K, 1atm   ΔHp     373.15K,1atm       ΔHv         373.15K,1 atm

∴ ΔHp = Qp = nCpΔT

∴ n H2O = 1 mol

∴ Cp,n = 75.3 J/mol.K

∴ ΔT = 373.25 - 298.15 = 75 K

⇒ Qp = (1 mol)*(75.3 J/mol.K)*(75K) = 5647.5 J

⇒ ΔHp = 5647.5 J = 5.6475 KJ

⇒ ΔH = ΔHp + ΔHv

∴ ΔHv = 40.79 KJ/mol * 1 mol = 40.79 KJ  

⇒ ΔH = 5.6475 KJ + 40.79 KJ = 46.4375 KJ

ideal gas:

∴ ΔH = ΔU + PΔV

∴ V1 = nRT1/P1 = ((1)*(0.082)*(298.15))/1 = 24.45 L

∴ V2 = nRT2/P2 = ((1)*(0.082)*(373.15))/ 1 = 30.59 L

⇒ ΔV = V2 - V1 = 6.15 L * (m³/1000L) = 6.15 E-3 m³

∴ P = 1 atm * (Pa/ 9.86923 E-6 atm) = 101325.027 Pa

⇒ ΔU = ΔH - PΔV = 46.4375 KJ - ((101325.027 Pa*6.15 E-3m³)*(KJ/1000J))

⇒ ΔU = 46.4375 KJ - 0.623 KJ

⇒ ΔU = 45.814 KJ

∴ ΔS = Cv,n Ln (T2/T1) + nR Ln (V2/V1)

⇒ ΔS = (75.3) Ln(373.15/298.15) + (1)*(8.314) Ln (30.59/24.45)

⇒ ΔS = 16.896 J/K + 1.863 J/K

⇒ ΔS = 18.76 J/K

3 0
3 years ago
True or false To obtain a salt, a metal must be combined with a hydroxide
Darya [45]

Answer:

False

Explanation:

The statement is implying that this is the only way to obtain a salt.  Any ionic compound is a salt.  For example, NaCl (table salt) is an ionic compound.  It is the combination of a nonmetal (Cl) and a metal (Na).

3 0
3 years ago
Read 2 more answers
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