Answer:
120.37 g
Explanation:
Mg = 24.31 g
S = 32.06 g
4 O = 16 X 4 = 64 g
Therefore, MgSO4 is (24.31 + 32.06 + 64) g = 120.37 g
At STP conditions the volume of 1 mol of any ideal gas will be 22.4L
0.500 mol C3H3 x 22.4L / 1 mol = 11.2 L
Answer:
health issues and physical encounters
Hey there!:
density = mass / volume
1.84 g/mL = 12 g / V
V = 12 / 1.84
V = 6.521 mL
hope this helps!
