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Setler [38]
3 years ago
8

Molecules can exist as: A)solids B) liquids C) gases D) all of the above

Chemistry
1 answer:
DerKrebs [107]3 years ago
6 0

I believe it is D. Hope this helps you!

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Convert 6.75 atm to torr Hg (using dimensional analysis method)
Naily [24]
Well, torr and Hg are different units, but they have the same conversiton with atm.  

The conversion for atm to torr or mmHg is 1 atm = 760 torr = 760 mmHg.

Because you have 6.75 atm you can find both the torr and mmHg.

To use dimensional analysis just make sure that you cancel out your units as you go.

6.75 atm * (760 torr / 1 atm) = 5130 torr or 5.13 x 10 to the -3 torr with significant figures.  

I hope this helped. 
5 0
4 years ago
A research team has just discovered a new element called Likhitium. Now they need to determine the average atomic mass in order
earnstyle [38]

The question is incomplete, the complete question is shown in the image attached to this answer.

Answer:

139.13

Explanation:

The average atomic mass of the element Likhitium is the sum of the relative abundance of all the isotopes of Likhitium.

We obtain the relative atomic mass of Likhitium as follows;

(44.7/100 * 138) + (52.3/100 * 139) + (0.5/100 * 140) + (2.5/100 * 141)

61.7 + 73.2 + 0.7 + 3.53 = 139.13

Hence the relative abundance of Likhitium is 139.13

6 0
3 years ago
Ethanol is a:<br>A. substance<br>B. heterogeneous mixture<br>C. homogenous mixture​
Dahasolnce [82]

Answer: i think it is A

Explanation:

hope this helps!

6 0
3 years ago
Read 2 more answers
I'll give brainliest!!
Ivahew [28]

Answer:

to mi understanding iz fusion reaction

6 0
3 years ago
Hydrogen is diffusing through solid nickel. At a temperature of 358 K, the diffusivity is 1.16 x 10-8 cm2/s. At a temperature of
Lelu [443]

Answer:

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

Explanation:

Consider the following equations:

lnD_{1} =lnD_{o} -\frac{Q_{d} }{R*T_{1} }

lnD_{2} =lnD_{o} -\frac{Q_{d} }{R*T_{2} }

Solving the above two equation to find the Q_d in term of diffusivity and temperature we will get:

Q_{d}=-R*\frac{lnD_{1} -lnD_{2} }{\frac{1}{T_{1} }-\frac{1}{T_{2} }  }

where:

Q_d is the activation energy

D_1 is the diffusivity at T_1

D_2 is the diffusivity at T_2

Q_{d}=-8.31*\frac{ln1.16*10^-12 -ln1.05*10^-11 }{\frac{1}{358 }-\frac{1}{438 }  }

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

3 0
4 years ago
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