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Veseljchak [2.6K]
2 years ago
15

a car speeds up from 12 m/s to 20 m/s in 6.4 s. if its mass is 1200kg, what force must its engine provide?

Physics
1 answer:
svet-max [94.6K]2 years ago
6 0

Answer:

1500 N

Explanation:

• Initial velocity, u = 12 m/s

• Final velocity, v = 20 m/s

• Time taken, t = 6.4 s

• Mass, m = 1200 kg

\longrightarrow F = ma

a = (v – u)/t, so

\longrightarrow F = 1200 × (20 – 12)/6.4

\longrightarrow F = 1200 × 8/6.4

\longrightarrow F = 1200 × 80/64

\longrightarrow F = 1200 × 40/32

\longrightarrow F = 1200 × 20/16

\longrightarrow F = 300 × 20/4

\longrightarrow F = 300 × 5

\longrightarrow F = 1500 N (Answer)

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To solve this exercise it is necessary to use the concepts related to Difference in Phase.

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3 years ago
What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a
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Complete Question

A certain refrigerator, operating between temperatures of -8.00°C and +23.2°C, can be approximated as a Carnot refrigerator.

What is the refrigerator's coefficient of performance? COP

(b) What If? What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump? COP

Answer:

a

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b

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Explanation:

From the question we are told that

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     The upper operation temperature of the refrigerator is   T_2 =  23.2 ^oC =  296.2 \  K

Generally the refrigerators coefficient of performance is mathematically represented as

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=>     COP =  \frac{265}{296.2 - 265  }

=>     COP = 8.49

Generally if a refrigerator (operating between the same temperatures) was instead used as a heat pump , the coefficient of performance is mathematically represented as

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=>         COP_1 =  \frac{296.2}{ 296.2 - 265 }  

=>         COP_1 = 9.49  

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3 years ago
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Answer:

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Explanation:

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⇒       =\frac{0.108}{9.8}

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