Answer: 62 μT
Explanation:
Given
Length of rod, l = 1.33 m
Velocity of rod, v = 3.19 m/s
Induced emf, e = 0.263*10^-3 V
Using Faraday's law, the induced emf of a rod can be gotten by the formula
e = blv where,
e = induced emf of the rod
b = magnetic field of the rod
l = length of the rod
v = velocity of the rod. On substituting, we have
0.263*10^-3 = b * 1.33 * 3.19
0.263*10^-3 = b * 4.2427
b = 0.263*10^-3 / 4.2427
b = 0.0000620 T
b = 62 μT
Thus, the strength of the magnetic field is 62 μT
Answer:

Explanation:
Given that:
Electrical field E = 
square side l = 5.0 m
Area A = 5.0 * 5.0
= 25.0 m²
Angle ( θ ) between area vector and E = (90° - 60°)
= 30°
The flux
can now be determined by using the expression
= 
=

=
= 
Answer:
The rate of change of magnetic field is 2.23 T/s.
Explanation:
Given that,
Dimension of rectangular coil is 7.2 cm by 3.7 cm.
Number of turns in the coil, N = 104
Resistance of the coil, R = 12.4 ohms
Current, I = 0.05 A
We need to find the rate of change of magnetic field in the coil. The induced emf is given by the rate of change of magnetic flux. So,

Ohm's law is :

So,

So, the rate of change of magnetic field is 2.23 T/s.
It's called the periodic table because it arranges the elements the into repeating sets known as periods. this is defined by the <span>covalence of an element and the number of electrons i has in its outermost shell. I feel the the Best answer would be B. sorry if im wrong but i hope i helped :)</span>
Answer:
Radius of cross section, r = 0.24 m
Explanation:
It is given that,
Number of turns, N = 180
Change in magnetic field, 
Current, I = 6 A
Resistance of the solenoid, R = 17 ohms
We need to find the radius of the solenoid (r). We know that emf is given by :


Since, E = IR




or

Area of circular cross section is, 


r = 0.24 m
So, the radius of a tightly wound solenoid of circular cross-section is 0.24 meters. Hence, this is the required solution.