<span>B)
The sample that Mrs. Craig took was too small.
I'm assuming the question is asking why they were not the same percentage?</span>
Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Hi there
The formula is
A=p (1+r)^t
A future value?
P present value 1000
R interest rate 0.07
T time 5 years
So
A=1,000×(1+0.07)^(5)
A=1,402.55
It's a
Hope it helps
Answer:
C
Step-by-step explanation:
I think that would be c not completely sure but I hope it helps
2x^3 + 2x^2 + 5x + 1/ x^2
