Answer : The equilibrium concentration of CO in the reaction is, 
Explanation :
The given chemical reaction is:
The expression for equilibrium constant is:
![K_c=\frac{[COCl_2]}{[CO][Cl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCOCl_2%5D%7D%7B%5BCO%5D%5BCl_2%5D%7D)
As we are given:
Concentration of 
at equilibrium = Concentration of 
So,
![K_c=\frac{[Cl_2]}{[CO][Cl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCl_2%5D%7D%7B%5BCO%5D%5BCl_2%5D%7D)
![K_c=\frac{1}{[CO]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B1%7D%7B%5BCO%5D%7D)
![1.2\times 10^3=\frac{1}{[CO]}](https://tex.z-dn.net/?f=1.2%5Ctimes%2010%5E3%3D%5Cfrac%7B1%7D%7B%5BCO%5D%7D)
![[CO]=8.3\times 10^{-4}M](https://tex.z-dn.net/?f=%5BCO%5D%3D8.3%5Ctimes%2010%5E%7B-4%7DM)
Therefore, the equilibrium concentration of CO in the reaction is,
No a molecule is 2 different atoms bond
Answer:
7.38654 in 54 grams
Explanation:
To get moles, you divide grams of a substance by molecular weight. The molecular weight of CO2 is 44 g/mol. 54g divided by 44/mol is 1.227moles.
You then need to multiply moles by Avogadro’s constant (6.022x10^23). That gives you 7.38654x10^23 molecules in 54 grams of CO2.
Answer:
It's called A polar covalent bond
Answer:
hydrogen bonds are also known as electrostatic dipole interaction
