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Oliga [24]
3 years ago
15

F

Chemistry
1 answer:
Airida [17]3 years ago
3 0

Answer:

Final pressure = 362.7 Pa

Explanation:

Given that,

Initial volume, V₁ = 930 ml

Initial pressure P₁ = 156 Pa

Final volume, V₂ = 400 mL

We need to find the final pressure. We know that the relation between volume and pressure is inverse i.e.

V\propto \dfrac{1}{P}\\\\\dfrac{V_1}{V_2}=\dfrac{P_2}{P_1}\\\\P_2=\dfrac{V_1P_1}{V_2}\\\\P_2=\dfrac{930\times 156}{400}\\\\P_2=362.7\ Pa

So, the final pressure is equal to 362.7 Pa.

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Why is the law of conservation of mass law and not a theory?
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Answer:

In physics and chemistry, the law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change, so quantity can neither be added nor be removed.

Explanation:

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3 years ago
What is the concentration of each ion in a solution that is prepared by dissolving 5.00 g of ammonium chloride in enough water t
sukhopar [10]

The concentration of each ion in the solution of ammonium chloride is:

  • NH₄⁺ = 0.1886 M
  • Cl⁻ = 0.1886 M

To solve this problem, the formulas and the procedures that we have to use are:

  • M = n(solute)/v(solution) L
  • n = m / MW
  • MW= ∑ AWT

Where:

  • M= molarity
  • n = moles
  • m = mass
  • v = volume
  • MW = molecular weight
  • AWT = atomic weight

Information about the problem:

  • m(NH₄Cl) = 5 g
  • v(solution) = 500 ml
  • AWT (N)= 14 g/mol
  • AWT (H)= 1 g/mol
  • AWT (Cl) = 35 g/mol

Converting the volume units from (ml) to (L) we have:

v(solution) = 500 ml * (1 L/1000 ml)

v(solution) = 0,50 L

We calculate the moles of the NH₄Cl from the MW:

MW = ∑ AWT

MW (NH₄Cl)= AWT (N) + AWT (H)*4 + AWT (Cl)

MW (NH₄Cl)= 14 g/mol +( 1 g/mol * 4) + 35 g/mol

MW (NH₄Cl)= 14 g/mol + 4 g/mol + 35 g/mol

MW (NH₄Cl)= 53 g/mol

Having the MW we calculate the moles of NH₄Cl:

n(NH₄Cl) = m(NH₄Cl) / MW(NH₄Cl)

n(NH₄Cl) = m(H2SO4) / MW (H2SO4)

n(NH₄Cl) =  5 g / 53 g/mol

n(NH₄Cl) = 0.0943 mol

Applying the molarity formula, we get:

M(NH₄Cl) = n(NH₄Cl)/v(solution) L

M(NH₄Cl) = 0.0943 mol / 0,50 L

M(NH₄Cl) = 0.1886 M

There are 0.1886 moles of NH₄Cl per liter of solution.

Let's recognize that 1 mol NH₄Cl contains:

  • 1 mol NH₄⁺
  • 1 mol Cl⁻

The concentration of each ion is thus:

(1)*(0.1886 M) = 0.1886 M NH₄⁺

(1)*(0.1886 M) = 0.1886 M Cl⁻

<h3>What is a solution?</h3>

In chemistry a solution is known as a homogeneous mixture of two or more components called:

  • Solvent
  • Solute

Learn more about chemical solution at: brainly.com/question/13182946 and brainly.com/question/25326161

#SPJ4

4 0
2 years ago
A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely
Rzqust [24]

Answer:

1.59 atm

Explanation:

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N_{2}O_{3}(g) - - -> NO_{2}(g)+NO(g)

The dalton's law tell us that the total pressure of a mixture of gases is the sum of the partial pressure of every gas.

So after the reaction the total pressure is:

P_{total}=P_{NO_{2}}+P_{NO}

we don't include N_{2}O_{3} because it decomposed completely.

Assuming  ideal gases

PV=nRT

P= pressure, V= volume of the container, n= mol of gas, R=constant of gases and T=temperature.

so moles of N_{2}O_{3} is:

n_{N_{2}O_{3}}=\frac{P_{1}V}{RT_{1}}

from the  reaction stoichiometry (1:1) we have that after the reaction the number of moles of each product is the same number of moles of N_{2}O_{3}.

n_{NO_{2}}=\frac{P_{1}V}{RT_{1}}

n_{NO}=\frac{P_{1}V}{RT_{1}}

The partial pressure of each gas is:

P_{NO_{2}}=\frac{n_{NO_{2}*R*T_{2}}}{V}

P_{NO}=\frac{n_{NO}*R*T_{2}}{V}

so total pressure is:

P_{total}=(n_{NO_{2}}+n_{NO})*\frac{R*T_{2}}{V}

replacing the moles we get:

P_{total}=(2*\frac{P_{1}V}{RT_{1}})*\frac{R*T_{2}}{V}

We know that T2=3*T1

replacing this value in the equation we get:

P_{total}=2*\frac{P_{1}V}{RT_{1}}*\frac{R*3T_{1}}{V}

P_{total}=6*P_{1} = 6*0.265 atm = 1.59 atm

5 0
3 years ago
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