Answer:
The ratio of net income in the first 6 months, to the last six months is $76,500 / $100,000. This simplifies intuitively as follows:
76500/100000
Dividing by 100: 765/1000
Dividing by 5: 153/200
The denominator 200 is only divisible by the prime numbers 2 and 5, and since the numerator 153 is not divisible by either 2 or 5, this means that this is in simplest form, and the final answer is 153/200.
Step-by-step explanation:
I hope this helps you
if in 350 students are 14 students were absent
in 100 students are ?
?.350=100.4
?=400/360
?=1.14%
The first step is to simplify the absolute value. 0.8 - 3/5 is equal to 0.8 - 0.6 which is 0.2. Now we do order of operations. Since the absolute value of 0.2 is 0.2, we can now do PEMDAS and solve. First is multiplication. 0.2 * 10 is 2. Now we have to do 5 - 3 which gives us our answer of 3, or C.
<h3>Answer:</h3>
F (3x, 3y)
<h3>Explanation:</h3>
Dilation about the origin multiplies each coordinate by the dilation factor. For some coordinates (x, y), dilation by a factor of 3 means the new coordinates are ...
... 3×(x, y) = (3x, 3y)
_____
<em>Comment on the problem</em>
The way the problem is worded, you expect an answer choice that will be specific to the coordinates of point A. There are none.
Instead, the answer choices are generic, corresponding to dilation of a point (x, y) by a factor of 3, translation up and to the right by 3, dilation by a factor of 1/3, and translation down and to the left by 3.
Answer:
x=2
y=3
Step-by-step explanation:
x/2+y/3=2 so
3x/6+2y/6=12/6
then multiply by 6
<em>3x+2y=12</em>
equation number 2
x/3+y/2=13/6
2x/6+3y/6=13/6
multiply by 6
<em>2x+3y=13</em>
so the system is now
<em>3x+2y=12</em>
<em>2x+3y=13</em>
<em>from the first equation 2y=12-3x, y=6 - 3x/2</em>
<em>then put y in the second equation</em>
<em>2x+3*(6-3x/2)=13</em>
<em>2x+18-9x/2=13</em>
<em>2x-9x/2=13-18</em>
<em>4x/2-9x/2=-5</em>
<em>-5x/2=-5</em>
<em>*(-1/5) *(-1/5)</em>
<em>x/2=1</em>
<em>*2 *2</em>
<em>x=2</em>
<em>so y=6-3*2/2=6-3</em>
<em>y=3</em>
<em></em>
<em></em>
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