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2 years ago

A collection of 6. 25×1018 electrons has the charge of.

Chemistry

1 answer:

Natali [406]2 years ago

7 0

Answer:

Explanation:

1)The charge of one electron is given by

1 e = - 1.6 * 10-19 C

Then – 1 C = 1 e / ( 1.6 * 10-19 )

= 6.25 * 1018 e

So one-coulomb charge has 6.25 * 1018 electrons

2)Let q1 and q2 be two charges separated by a distance r

Then q1 = - 40 µC = - 40 * 10-6 C

And q2 = 108 µC = 108 * 10-6 C

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Describe a Sankey Diagram and how it can be used.

jolli1 [7]

Explanation:

Sankey diagrams , which are typically used to visualize energy transfers between processes, are named after the Irishman Matthew H. P. R. Sankey, who used this type of diagram in a publication on energy efficiency of a steam engine in 1898.

Sankey diagrams are ideal for visually representing energy balances.

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2 years ago

The atomic nucleus contains?

ycow [4]

The nucleus, that dense central core of the atom, contains both protons and neutrons. Electrons are outside the nucleus in energy levels. Protons have a positive charge,neutrons have no charge, and electrons have a negative charge. A neutral atom contains equal numbers of protons and electrons.

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3 years ago

Write the formula for methionine (red = o, gray = c, blue = n, yellow = s, ivory = h).express your answer as a molecular formula

-BARSIC- [3]

We have to get the formula of methionine.

The formula of methionine is

Methionine is an essential amino acid of human. It is white crystalline solid.

The formula of methionine is C₅H₁₁NO₂S. Methionine contains five carbon atoms, eleven hydrogen atoms, one nitrogen atom, two oxygen atoms and one sulphur atom.

It contains one amino group (-NH₂) and one carboxylic acid group (-COOH). Atoms are depicted in C-atom in grey, H-atom in ivory, O-atom in red, N-atom in blue and S-atom in yellow.

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3 years ago

Calculate the freezing point of a 0.08500 m aqueous solution of nano3. the molal freezing-point-depression constant of water is

Citrus2011 [14]

Depression in freezing point (Δ $T_{f}$ ) = $K_{f}$ ×m×i,
where, $K_{f}$ = cryoscopic constant = $1.86^{0} C/m$ ,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For $NaNO_{3}$ )

Thus, (Δ $T_{f}$ ) = 1.86 X 0.0085 X 2 = $0.03162^{0}C$

Now, (Δ $T_{f}$ ) = $T^{0}$ - T
Here, T = freezing point of solution
$T^{0}$ = freezing point of solvent = $0^{0}C$
Thus, T = $T^{0}$ - (Δ $T_{f}$ ) = - $0.03162^{0}C$

8 0

3 years ago

Read 2 more answers

Determine the oxidation state of each of the following species.<br> Pb2+

mafiozo [28]

Answer:

Pb oxidation number is +2

C in CH4 is -4. H is +1. 4H + 1C = 0. ; 4(+1) + C = 0 ; C = -4

O is usually -2. 3O = 3(-2) = -6. ; 2Fe =. +6 ; each Fe is +3

2Ag = +2 since O = -2 ; each Ag = +1

6 0

3 years ago