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Roman55 [17]
4 years ago
15

How many significant digits in 0.23100

Chemistry
1 answer:
Reil [10]4 years ago
4 0

Answer:

There are 5 significant digits in 0.23100.

Explanation:

This is because all non-zero digits are considered significant and zeros after decimal points are considered significant.

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Answer:

C I’m sure

Explanation:

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3 years ago
Which one of the following is a solution? salt water sugar oxygen chocolate chip cookies
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I believe the awnser is salt water i took a test on it recently and that was the awnser.

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If CO2 is not removed by boiling the solution after the addition of HCl, how will this affect the amount of NaOH required to rea
zimovet [89]

Answer:

See explanation

Explanation:

CO2 reacts with water to form carbonic acid as follows;

CO2(g) + H2O(l) ---------> H2CO3(aq)

This makes the solution more acidic hence it will require more NaOH to reach end point due to the increase in acidity.

Hence, if CO2 is not removed by boiling the solution, a greater amount of NaOH is required to reach end point.

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In two or more complete sentences explain how to balance the chemical equation, KClO3 ⟶ KCl + O2 and include all steps. Write yo
Serggg [28]

Answer:

2KClO3 -------> 2KCl + 3O2

Explanation:

First, in balancing a chemical reaction such as the one given in the question, you should understand that for an equation to be balanced, the number of atoms and ions on both sides of the equation that is the right and left side must be equal. This follows the law of conservation of mass which tells us that matter can neither be created nor destroyed but can be changed into another form.

Next is to begin balancing the equation by identifying and writing down the substances given:

KCl03 ---------> KCl + O2

Next is to count he number of the individual atoms on each side and find out if they are the same on both sides and if not you must follow the next step.

Add a corresponding number and use it to multiply the atoms involved

KClO3 ---------> KCl + O2

Oxygen is 3 on the left side and two on the other side, so we multiply the left hand side by 2 and the right hand side by 3

2KClO3 -----> KCl + 3O2

The potassium and Chlorine are no longer balanced, so you multiply the right had=nd side of KCl by 2.

2KClO3 -----> 2KCl + 3O2

The reactionis herefore balanced as both sides have equal number of atoms and ions.

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3. What is the substance ozone?
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