Answer:
j = 0 or j = 30
Step-by-step explanation:
j² - 30j = 0
Factorise j out of both terms on the left side.
j (j-30) = 0
Apply zero product rule.
j = 0 or j-30 = 0
Find the value of j.
j = 0 or j = 30
(A) 32.12 = 8.8 x t
(B) If you round the numbers to 32 and 8 you can see that 8 x 4 = 42 are 4 is positive.
(C) 32.12 / 8.8 = 3.65
Answer:
function 2
Step-by-step explanation:
i looked at the table, and since t (which is the x-coordinate in this case) was 0, that means that 5.25 is the y-coordinate and is greater than 5 in the first equation.
Answer:
B) To represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
Step-by-step explanation:
Here the point A is given as 3 on number line.
Point B is given as -5 on number line.
To find : IA-BI
The distance between any two point A and B is given as IA-BI.
Now, to find the absolute value:
IA-BI = I (3) - (-5)I
or, IA-BI = I (3) + 5I = I8I
= 8 units
or, IA-BI = 8 units
Hence, on the number line, the distance between -5 and 3 is 8 units.
And, to represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
Asssuming blanks are plus
5(x+1)=4(x+8)
distribute
a(b+c)=ab+ac
5(x+1)=5x+5
4(x+8)=4x+32
5x+5=4x+32
minus 4x from both sides
x+5=32
minus 5 from both sides
x=27
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