<h2>
The magnitude 24 (
) of the acceleration of the particle when the particle is not moving.</h2>
Explanation:
Given,
A particle moving along the x-axis has a position given by
m ........ (1)
To find, the magnitude ( ) of the acceleration of the particle when the particle is not moving = ?
Differentiating equation (1) w.r.t, 't', we get
⇒ 
....... (2)
⇒ 
⇒ 
⇒ t = 2 s
Again, differentiating equation (2) w.r.t, 't', we get
Put t = 2, we get
Thus, the magnitude 24 ( ) of the acceleration of the particle when the particle is not moving.
Answer:
0.903 seconds
Explanation:
To find how many seconds the acorn fall, we can use the formula for distance travelled with constant acceleration:
D = Vo*t + a*t^2/2,
where D is the distance travelled, Vo is the inicial speed, t is the time and a is the acceleration.
In our problem:
Vo = 0,
a = g = 9.81 m/s2,
D = 4 meters.
So, we can solve the equation to find the time:
4 = 0*t +9.81*t^2/2
4.905*t^2 = 4
t^2 = 4/4.905 = 0.8155
t = 0.903 seconds
Answer:
The 80 mph car
Because the formula says 1/2 mass but for the velocity it is squared
Answer
given,
focal length of lens A = 5.77 cm
focal length of lens B= 27.9 cm
flies distance from mirror = 11.3 m
now,
Using lens formula
q =11.79 cm
image of lens A is object of lens B
distance of lens = 59.9 - 11.79 = 48.11
now, Again applying lens formula
q' =66.41 cm
hence, the image distance from the second lens is equal to q' =66.41 cm
