In addition to a reference point you also need distance and _________

A meter stick with a mass of 0.167 kg is pivoted about one end so it can rotate without friction about a horizontal axis. The me

SSSSS [86.1K]

Answer:

Part a)

change in potential energy is given as

$\Delta U = 0.82 J$

Part B)

angular speed of the rod is given as

$\omega = 5.42 rad/s$

Part c)

Linear speed of the end of the rod is given as

$v = 5.42 m/s$

Part d)

when a particle falls from rest to distance d = 1 m

$v = 4.42 m/s$

Explanation:

Part A)

As we know that the gravitational potential energy change is given as

$\Delta U = mgH$

$\Delta U = 0.167(9.81)(0.5)$

$\Delta U = 0.82 J$

Part B)

As we know that change in gravitational energy is equal to gain in kinetic energy

so we have

$\Delta U = \frac{1}{2}I\omega^2$

$0.82 = \frac{1}{2}(\frac{mL^2}{3})\omega^2$

$\omega^2 = \frac{6 \times 0.82}{0.167 (1)^2}$

$\omega = 5.42 rad/s$

Part c)

Linear speed of the end of the rod is given as

$v = L\omega$

$v = 5.42 m/s$

Part d)

when a particle falls from rest to distance d = 1 m

so we will have

$v = \sqrt{2gL}$

$v = \sqrt{2(9.81)(1)}$

$v = 4.42 m/s$

4 0

3 years ago

A car of mass 940.0 kg accelerates away from an intersection on a horizontal road. When the car speed is 42.5 km/hr (11.8 m/s),

MAVERICK [17]

Answer:

0.39 $m/s^2$

Explanation:

Parameters given:

Mass of car, m = 940 kg

Speed of car, v = 11.8 m/s

Power supplied by engine, P = 4300 W

To get the acceleration, we must define the relationship between Power and velocity.

Power, P, is given in terms of velocity, v, as:

P = F * v

where F = force

This is because Power is given as:

$P = \frac{E}{t} \\\\\\P = \frac{F*d}{t} \\\\\\=> P = F * v$

(where E = energy. t = time taken, d = distance moved)

Force, F, is given as:

F = m*a

Therefore, Power will be:

P = m * a * v

Acceleration, a, will then be:

$a = \frac{P}{m*v}$

$a = \frac{4300}{940 * 118} \\\\\\a = 0.39 m/s^2$

The acceleration of the car at that time is 0.39 $m/s^2$

4 0

2 years ago

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If a steady magnetic field exerts a force on a moving charge, that force is directed

lesya [120]

Answer:

C) at right angles to the direction of the motion

Explanation:

The magnetic force exerted on a charged moving particle is given by

$F=qvBsin \theta$

where

q is the charge of the particle

v is the velocity of the particle

B is the magnetic field intensity

$\theta$ is the angle between the direction of v and B

Moreover, the direction of the force is perpendicular to both v and B. In particular, the direction can be found by using the right hand rule:

- index finger: direction of the velocity

- middle finger: direction of the magnetic field

- thumb: direction of the force (if the charge is positive, otherwise the direction must be reversed if the charge is negative)

4 0

3 years ago

. At what velocity will the box in Problem 6 be traveling when it hits the ground? Use formula: Va = Vf - Vi / 2

VladimirAG [237]

Answer:

How much time does his victim on the ground below have to move out of harm's way? At what velocity will the safe hit the ground? sownt d-200m. n a = 100/2. Vi-o.

Explanation:

5 0

2 years ago

How was bohr atomic model similar to Rutherford's model

Juliette [100K]

Both believe that an atom contains negative charges and positive charges.
But both were different in the placement of charges

6 0

3 years ago

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In addition to a reference point you also need distance and __________ to describe location