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Klio2033 [76]
2 years ago
14

Which one of the following statements does not accurately describe the diatonic scale as it corresponds to the setup on a piano

keyboard?
A. The white keys are used to produce frequencies for the key of C.
B. Striking a key on a piano keyboard produces a sound with a specific frequency.
C. A scale would include a series of eight notes, where the first and seventh notes have the same letter.
D. The black keys are used to produce the five notes that correspond to additional frequencies on the even-tempered scale for the key of C.
Physics
2 answers:
Gekata [30.6K]2 years ago
8 0
<span>The answer is C. A scale would include a series of eight notes, where the first and seventh notes have the same letter.

Just took the test. Got 100%
</span>
Eduardwww [97]2 years ago
8 0

Answer:

A

Explanation:

The diatonic scale consists of seven notes, namely C,D,E,F,G,A,B (C major scale) on a Keyboard, these notes are the white ones. The black and white ones on the keyboard scales are called Chromatic scale.

A scale besides having seven notes, it must have 5 tones intervals and 2 half tones (E-F and  C-B, for the C major scale)

As the note after B, is C. And the C major scale is completely diatonic, and also a frequency does it's not only related to C scale. The answer is A.

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Answer:

D=1693742.7m

Explanation:

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A 500-N weight sits on the small piston of a hydraulic machine. The small piston has area 2.0 cm2. If the large piston has area
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Answer:

W₂= 10000 N

Explanation:

Pascal´s Principle can be applied in the hydraulic press:

If we apply a small force (F1) on a small area piston A1, then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F2) can be exerted that is proportional to the area (A2) of the piston:

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\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }

F_{2} = \frac{F_{1}*A_{2}  }{A_{1}}  Equation (1)

Data

W₁ = weight sits on the small piston

F₁ = W₁= 500 N

A₁ = 2.0 cm²

A₂ = 40 cm²

Calculation of the weight  (W₂) can the large piston support

We replace data in the equation (1)

F_{2} = \frac{(500)*(40) }{2}

F₂ = 10000 N

W₂= F₂= 10000 N

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