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Klio2033 [76]
3 years ago
14

Which one of the following statements does not accurately describe the diatonic scale as it corresponds to the setup on a piano

keyboard?
A. The white keys are used to produce frequencies for the key of C.
B. Striking a key on a piano keyboard produces a sound with a specific frequency.
C. A scale would include a series of eight notes, where the first and seventh notes have the same letter.
D. The black keys are used to produce the five notes that correspond to additional frequencies on the even-tempered scale for the key of C.
Physics
2 answers:
Gekata [30.6K]3 years ago
8 0
<span>The answer is C. A scale would include a series of eight notes, where the first and seventh notes have the same letter.

Just took the test. Got 100%
</span>
Eduardwww [97]3 years ago
8 0

Answer:

A

Explanation:

The diatonic scale consists of seven notes, namely C,D,E,F,G,A,B (C major scale) on a Keyboard, these notes are the white ones. The black and white ones on the keyboard scales are called Chromatic scale.

A scale besides having seven notes, it must have 5 tones intervals and 2 half tones (E-F and  C-B, for the C major scale)

As the note after B, is C. And the C major scale is completely diatonic, and also a frequency does it's not only related to C scale. The answer is A.

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A 99.1-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is μk =
Stels [109]

Answer:

628.022466 N

8.61 m/s

Explanation:

m = Mass

\mu = Coefficient of friction

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

F_f=\mu mg\\\Rightarrow F_f=0.646\times 99.1\times 9.81\\\Rightarrow F_f=628.022466\ N

Magnitude of frictional force is 628.022466 N

F=ma\\\Rightarrow a=\frac{F_f}{m}\\\Rightarrow a=\frac{628.022466}{99.1}\\\Rightarrow a=6.33726\ m/s^2

v=u+at\\\Rightarrow 0=u-6.33726\times 1.36\\\Rightarrow u=8.61\ m/s

Initial speed of the player is 8.61 m/s

4 0
3 years ago
What is the best free energy source?<br> Nuclear<br> Solar<br> Natural Gas
Free_Kalibri [48]
Solar it is the cheapest and widely used energy source
4 0
3 years ago
Two parallel plates of area 2.34*10-3 M2 have 7.07*10-7C of charge placed on them. A6.62*10-5C charge q1 is placed between the p
ira [324]

Answer:

The force exerted on the q_1 is  F =  2.25*10^{3} \ N

Explanation:

From the question we are told that

     The area is  A =  2.34*10^{-3} \ m^2

     The magnitude of charge placed on them is  q =  7.07 * 10^{-7} C

     The charge placed between the plate is q_1 = 6.62 *10^{-5} C

   

The electric field generated around the plate  is mathematically represented as

           E =  \frac{q}{A \epsilon_o}

Substituting values

          E =  \frac{7.07*10^{-7}}{2.34*10^{-3} * 8.85 *10^{-12}}

         E = 34*10^{6} \ V/m

The force exerted the charge q_1 is  mathematically represented as

        F =  q_1 * E

Substituting values  

        F =  6.62 *10^{-5} * 34*10^{6}

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8 0
3 years ago
Two samples of water are mixed together.
horrorfan [7]

Let the cold water go up x degrees.

Let the hot water go down 100 - x degrees.

The formula for heat exchange is m*c*delta t

Givens

Ice

deltat = x

m = 0.50 kg

c = 4.18

Hot water

deltat = 100 - x

m = 1.5 kg

c = 4.18

Formula

The heat up = heat down

0.50 * c * x = 1.5 * c * (100 - x)            Divide both sides by c

Solution

0.50 *x = 1.5*(100 - x)                          Remove the brackets.

0.5x = 150 - 1.5x                                  Add 1.5x to both sides.

0.5x + 1.5x = 150 - 1.5x + 1.5x             Combine like terms  

2x = 150                                               Divide by 2

x = 75

Answer

A

6 0
3 years ago
A 3.00-kg ball swings rapidly in a complete vertical circle of radius 2.00 m by a light string that is fixed at one end. The bal
Setler [38]

Answer

given,

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   work done by the gravity = ?          

   work done by the tension = ?            

Work done by the gravity = - m g Δh            

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work done by gravity is equal to -117.6 J            

Work done by tension will be equal to zero.        

Zero because tension is always perpendicular to velocity

work done by tension is equal to 0 J                          

7 0
3 years ago
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