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3 years ago

Just one question. please help, thank you!!!

Physics

1 answer:

Bas_tet [7]3 years ago

7 0

Answer:

Answer 5: Tension

Answer 3: Compression

Answer 4: Example 2

Answer 2: Oceanic Crust and Continental Crust

Answer 1: Continental Crust

Explanation:

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Why are circuits important?

padilas [110]

You should draw a diagram of each for this question.
In a series circuit, the resistors experience the same current. In a parallel circuit, they have the same voltage drop. Therefore, the equivalent resistance is calculated differently for a series and parallel circuit.
Ohm's law: V=IR
Resistance keeps a circuit from shorting.

6 0

3 years ago

Consider two laboratory carts of different masses but identical kinetic energies and the three following statements. I. The one

kolbaska11 [484]

Answer:

d) I and III only.

Explanation:

Let be $m_{1}$ and $m_{2}$ the masses of the two laboratory carts and let suppose that $m_{1} > m_{2}$ . The expressions for each kinetic energy are, respectively:

$K = \frac{1}{2}\cdot m_{1}\cdot v_{1}^{2}$ and $K = \frac{1}{2}\cdot m_{2}\cdot v_{2}^{2}$ .

After some algebraic manipulation, the following relation is constructed:

$\frac{m_{1}}{m_{2}} = \left(\frac{v_{2}}{v_{1}}\right)^{2}$

Since $\frac{m_{1}}{m_{2}} > 1$ , then $\frac{v_{2}}{v_{1}} > 1$ . That is to say, $v_{1} < v_{2}$ .

The expressions for each linear momentum are, respectively:

$p_{1} = \frac{2\cdot K}{v_{1}} = m_{1}\cdot v_{1}$ and $p_{2} = \frac{2\cdot K}{v_{2}} = m_{2}\cdot v_{2}$

Since $v_{1} < v_{2}$ , then $p_{1} > p_{2}$ . Which proves that statement I is true.

According to the Impulse Theorem, the impulse needed by cart I is greater than impulse needed by cart II, which proves that statement II is false.

According to the Work-Energy Theorem, both carts need the same amount of work to stop them. Which proves that statement III is true.

6 0

3 years ago

One system consists of two like charges (q1 and q2) separated by a distance r. A second system consists of two charges that are

olganol [36]

fyt as per the question the magnitude of two like charges are given as q1 and q2.the separation distance is given as r unit.hence the potential energy is given as- $P.E=+\frac{1}{4\pi\epsilon} \frac{q1*q2}{r^2}$

here the potential energy is positive which means the force between two charges is repulsive.the potential energy is maximum which indirectly denotes that the system is unstable.due to this repulsion the smaller charge may accelerate.

coming to the same charges of opposite nature i.e unlike charges-here the magnitude of charges are same and separation distance is also are,so the potential energy will be given as- $P.E=-\frac{1}{4\pi\epsilon}\frac{q1*q2}{r^2}$

here the potential energy is negative .so the system of two charges are attracted by each other.

4 0

4 years ago

Read 2 more answers

An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time

Arisa [49]

Explanation:

Distance = (intial speed)X(Time) + 1/2(acceleration)X(Time) [Third equation of motion]

As initial speed is zero, therefore;

Distance = 1/2(acceleration)X(Time)

= 1/2 (6 X 15)

= 1/2 (90)

= 45 meters

Hence, the object traveled 45 meters.

4 0

4 years ago

Ultrasound is the name given to frequencies above the human range of hearing True or false

gulaghasi [49]

Yes. That's a true statement. Ultrasound is indeed the name given to sounds with frequencies above the human range of hearing.

Ultrasound is not different from "normal" (audible) sound in its physical properties, except that humans can't hear it.

5 0

3 years ago