Answer:
They are both mechanical waves
Answer:
hence the relative intensity is 3.0279 ×
Explanation:
Given data
wavelength 755.0 nm = 755 × m
width d = 2.20 µm = 2.20× m
screen distance D = 26.5 cm
I/Imax Yn = 13.0 cm
to find out
the relative intensity
solution
we know that
tanθ = Yn / D
here Yn is the distance from central maximum and D is here distance from screen put all these value
tanθ = 13 / 26.5
θ = 26.13 degree
so
relative intensity of light will be here
I/ Imax = (sinФ/Ф)² ................1
here Ф is angle that is
Ф = πdsinθ / wavelength
Ф = π(2.20×)sin26.13 / ( 755 ×)
Ф = 7.689
so we put Ф = 7.689 in equation 1
I/ Imax = (sinФ/Ф)²
I/ Imax = (sin7.689/7.689)²
I/ Imax = 3.0279 ×
hence the relative intensity is 3.0279 ×
Complete question:
The recoil of a shotgun can be significant. Suppose a 3.6-kg shotgun is held tightly by an arm and shoulder with a combined mass of 15.0 kg. When the gun fires a projectile with a mass of 0.040 kg and a speed of 380 m/s, what is the recoil velocity of the shotgun and arm–shoulder combination?
Answer:
The recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s
Explanation:
Given;
combined mass of the shotgun and arm–shoulder, m₁ = 15 kg
mass of the projectile, m₂ = 0.04 kg
speed of the projectile, u₂ = 380 m/s
let the recoil velocity of the shotgun and arm–shoulder combination = u₁
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = 0
m₁u₁ = - m₂u₂
Therefore, the recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s
Answer:
gravity
Explanation:
Though gravity holds planets, stars, solar systems and even galaxies together, it turns out to be the weakest of the fundamental forces, especially at the molecular and atomic scales.
Answer:
however your doing it now?? ?? lol