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tatiyna
3 years ago
9

This model shows a ball being shot from the cannon. Which of these statements accurately describes the energy of the cannonball?

Select ALL that apply. A) The kinetic energy is lowest at point E. B) The potential energy is lowest at point E. C) The kinetic energy is greatest at point C. D) The potential energy is greatest at point C. E) The ball changes from kinetic to potential energy at point A.
Physics
1 answer:
Fudgin [204]3 years ago
5 0

The potential energy of the model will be the greatest at point C while it will be the least at point E. Option B and D are correct.

<h3>What is potential energy?</h3>

The potential energy of an object is due to its position. It can be given as the formula,

U = mgh

Where,  

U - potential energy

m - mass

g - gravitation acceleration

h - height

From the formula since the mass and gravitation acceleration is constant, the potential energy of the model will depend upon the height only.

The potential energy will be greatest at point C because the relative position of the ball is the highest from the earth.

The potential energy will be lowest at point E because the height of the ball is the least in this position.

Therefore, the potential energy of the model will be the greatest at point C while it will be the least at point E.

Learn more about kinetic energy:

brainly.com/question/26320744

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What happens to the amplitude of the resultant wave when two sound waves with equal amplitude constructively interfere?
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Three moles of an ideal gas with a molar heat capacity at constant volume of 4.9 cal/(mol∙K) and a molar heat capacity at consta
Sergeu [11.5K]

Answer:

The heat flows into the gas during this two-step process is 120 cal.

Explanation:

Given that,

Number of moles = 3

Heat capacity at constant volume = 4.9 cal/mol.K

Heat capacity at constant pressure = 6.9 cal/mol.K

Initial temperature = 300 K

Final temperature = 320 K

We need to calculate the heat flow in to gas at constant pressure

Using formula of heat

\Delta H_{1}=nC_{p}\times\Delta T

Put the value into the formula

\Delta H_{1}=3\times6.9\times(320-300)

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We need to calculate the heat flow in to gas at constant volume

Using formula of heat

\Delta H_{1}=nC_{v}\times\Delta T

Put the value into the formula

\Delta H_{1}=3\times4.9\times(300-320)

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We need to calculate the heat flows into the gas during two steps

Using formula of total heat

\Delta H_{T}=\Delta H_{1}+\Delta H_{2}

\Delta H_{T}=414-294

\Delta H_{T}=120\ cal

Hence, The heat flows into the gas during this two-step process is 120 cal.

7 0
4 years ago
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