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IceJOKER [234]
4 years ago
5

Rearrange the equation to solve for the permeability of free space (μ0). Remember that the slope is the ratio of magnetic field

to current or μ0 = 2R N B I . Hint: Substitute your value of slope into the equation in place of B / I. μ0 = T · m/A

Physics
1 answer:
IRINA_888 [86]4 years ago
6 0

Complete Question

The complete question is shown on the first uploaded image

Compare the percent error between your value and the accepted value of 1.26 times 10-6 T · m/A. (Use the accepted value given to three significant figures in your calculation.). 100% % error = %

Answer:

The permeability of free space is \mu_0 = 1.32*10^{-6} \ Tm/A

The percentage error is  % error = 5.25%

Explanation:

From the question we are told that

            The slope is  s= 3.9\  G/A , and

Generally  1 \ gauss =  10^{-4 } tesla

               So  s = 3.9 *10^ {-4} T /A

From the relation given in the question

                        \mu_0 = \frac{2R}{N} [\frac{B}{I} ]

 Where R is the radius of the coil  =\frac{Diameter \ of \ coil }{2} = 0.017m

             N is the number of loops of the coil = 10

Now from the question we are told that

                  s = \frac{B}{I}

substituting into the equation above

               \mu_0 = \frac{2R }{N} s

Substituting values

              \mu_0= \frac{2 * 0.017}{10 } * 3.9*10^{-4}

                   = 1.326 *10^ {-6} \ Tm/A

Generally the % error is mathematically represented as

                    %error = \frac{Measured \  value - accepted \ value}{accepted \  value } *100

Given that the accepted value is \mu_o_ {acc} = 1.26 *10 ^{-6} \ T \cdot m /A

      Hence substituting values

                      %error  = \frac{(1.326-1.26)*10^{-6}}{1.26 *10 ^ {-6}} *100

                                  = 5.24

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Answer:

0.363999909622

Explanation:

F = Force

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ρ = Density of air = 1.21 kg/m³

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F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622

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