A cyclist turns a corner with a radius of 50m at a speed of 10m/s. What is the cyclist's acceleration?
1 answer:
2m/s²
Explanation:
Given parameters:
Radius = 50m
Speed = 10m/s
Unknown:
Acceleration of the cyclist
Solution:
The acceleration of the cyclist is directed inside of the corner because his motion is inward. This is a form of centripetal acceleration;
Centripetal acceleration is given by;
a =
v is the velocity
r is the radius
a = = 2m/s²
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Answer:
the magnitude of the torque on the permanent magnet = 7.34×10⁻³ Nm
the potential energy (in J) of the system consisting of the permanent magnet and the magnetic field provided by the coils = -1.0485 ×10⁻² J
Explanation:
The torque is given by :
where ;
m = 0.160 A.m²
B = 0.0800 T
θ = 35°
So the magnitude of the torque N = mBsinθ
N = (0.160)(0.0800)(sin 35°)
N = 0.007341
N = 7.34×10⁻³ Nm
Hence, the magnitude of the torque on the permanent magnet = 7.34×10⁻³ Nm
b) The potential energy
U = -mBcosθ
U = (- 0.160)(0.0800)(cos 45)
U = -0.010485
U = -1.0485 ×10⁻² J
Thus, the potential energy (in J) of the system consisting of the permanent magnet and the magnetic field provided by the coils = -1.0485 ×10⁻² J