1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
8_murik_8 [283]
3 years ago
9

In this experiment, you will measure mass and volume of various sport balls, both regularly shaped ball and irregularly shaped.

What property of an object can you determine using mass and volume? In the space below, write a scientific question that you will answer by doing this experiment.
Chemistry
2 answers:
Marina86 [1]3 years ago
5 0
You can measure density. Question options: Are mass and volume related? How does a mass or volume change affect density?
kicyunya [14]3 years ago
4 0

Answer: Density can be measured using mass and volume.

Explanation:

Mass is defined as the actual matter which an object comprises.

Volume is defined as the amount of space occupied by the object measured in cubic units.

The relation between these two quantities defines a property which is known as density.

Density is the ratio of an object's mass to its volume. The S.I. unit for this property is kg/m^3. It can also be expressed in g/cm^3

Mathematically,

Density=\frac{Mass}{Volume}      ...(1)

Question related to this topic: A rock of mass 45 grams has a volume of 15cm^3. Determine the density of the given rock.

Answer: We are given

Mass of the rock = 45 g

Volume of the rock = 15cm^3

Putting values in equation 1, we get:

Density=\frac{45g}{15cm^3}=3g/cm^3

From the above example, we conclude that mass and volume are related to determine density of any object.

You might be interested in
what pressure is generated when 5 mol of ethane is stored in a volume of 8 dm 3 at 25°C? Base calculations on each of the follow
Goshia [24]

Answer:

a) 40,75 atm

b) 30,11 atm

Explanation:

The Ideal Gas Equation is an equation that describes the behavior of the ideal gases:

                                     PV = nRT

where:

  • P = pressure [atm]
  • V = volume [L]
  • n = number of mole of gas [n]
  • R= gas constant = 0,08205 [atm.L/mol.°K]
  • T=absolute temperature [°K]

<em>Note: We can express this values with other units, but we must ensure that the units used are the same as those used in the gas constant.</em>

The truncated virial equation of state, is an equation used to model the behavior of real gases. In this, unlike the ideal gas equation, other parameters of the gases are considered as the <u>intermolecular forces</u> and the <u>space occupied</u> by the gas

\frac{Pv}{RT} = 1 + \frac{B}{v}

where:

  • v is the molar volume [L/mol]
  • B is the second virial coefficient [L/mol]
  • P the pressure [atm]
  • R the gas constant = 0,08205 [atm.L/mol.°K]

a) Ideal gas equation:

We convert our data to the adecuate units:

n = 5 moles

V = 3 dm3 = 3 L

T = 25°C = 298°K

We clear pressure of the idea gas equation and replace the data:

PV = nRT ..... P = nRT/V = 5 * 0,08205 * 298/3 =40,75 atm

b) Truncated virial equation:

We convert our data to the adecuate units:

n = 5 moles

V = 3 dm3 = 3 L

T = 25°C = 298°K

B = -156,7*10^-6 m3/mol = -156,7*10^-3 L/mol

We clear pressure of the idea gas equation and replace the data:

\frac{Pv}{RT} = 1 + \frac{B}{v} ...... P = (1 + \frac{B}{v}) \frac{RT}{v}

and v = 3 L/5 moles = 0,6 L/mol

P = (1 + \frac{-156,7*10^{-3} }{0,6} ) \frac{0,08205*298}{0,6} = 30,11 atm

5 0
3 years ago
Help with this question plz
Triss [41]
Increase, because you need heat to melt a solid to a liquid, so the temperature will have to get greater.
6 0
3 years ago
PLZ HELP, GIVING BRAINLIEST!!
andrew-mc [135]

Answer:

Option B. Decreasing the temperature of the solvent

Explanation:

Solubility is mostly enhanced by increasing the temperature of the solvent or solution. This means that am increase in temperature will increase the solubility and decreasing the temperature will decrease the solubility.

5 0
3 years ago
Read 2 more answers
The standard enthalpy of formation (ΔHf°) of calcium carbonate is –1207 kJ/mol. Which ONE of the equations below has ΔH° = –1207
Art [367]

Answer:

A) Ca(s) + C(s) + 3/2 O₂(g) → CaCO₃(s)

Explanation:

Standard enthalpy of formation of a chemical is defined as the change in enthalpy durin the formation of 1 mole of the substance from its constituent elements in their standard states.

The consituent elements of calcium carbonate, CaCO₃, in their standard states (States you will find this pure elements in nature), are:

Ca(s), C(s) and O₂(g)

That means, the equation that represents standard enthalpy of CaCO₃ is:

<h3>A) Ca(s) + C(s) + 3/2 O₂(g) → CaCO₃(s)</h3><h3 />

<em>Is the equation that has ΔH° = -1207kJ/mol</em>

3 0
3 years ago
What is the term for the number of protons in the nucleus of each atom of an element?
xxTIMURxx [149]

Answer:

atomic number

Explanation:

atomic number is the number of protons

5 0
2 years ago
Other questions:
  • Which has a greater ionization energy, Ne or Gallium?
    6·1 answer
  • combustion analysis of an unknown compound provides the following data: 73.5 grams carbon (C), 4.20 grams hydrogen (H) and 72.3
    11·1 answer
  • HELP!!! PLEASE!!!
    6·1 answer
  • Greg checks his watch one day at noon when the Sun is directly overhead. He decides to check his watch when the Sun is directly
    14·1 answer
  • 98 POINTS!
    10·2 answers
  • A reaction produces 0.755 mol of H2O. How many molecules of water are produced?
    6·1 answer
  • What is solubility?
    7·2 answers
  • 5. Which happens last in the process of photosynthesis?
    8·1 answer
  • What happens when warm air rises? (5 points)
    6·2 answers
  • Research the compositions of Pennies. What was the composition of each of your Pennies prior to treatment
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!