Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
1 answer:
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Answer:
a)
b) is the limiting reagent
c) Moles of produced = 2.45 mol
b) Moles of left = 1.75 -1.22 = 0.53
Explanation:
a) Balanced reaction:
b)
No. of mole of
No. of mole of
As, it is clear from the reaction that,
1 mol of requires 3 moles of
1.75 mol of require = 1.75 × 3 = 5.25 mol of
As, only 3.68 mol of is present, so
is the limiting reagent.
c)
3 moles of form 2 moles of
3.68 moles of will form =
d)
is present in excess.
3 moles of requires 1 mol of
3.68 moles of will require =
left = 1.75 -1.22 = 0.53 mol