Question

What is the energy of a photon of infrared radiation with a frequency of 2. 53 × 1012 Hz? Planck’s constant is 6. 63 × 10–34 J • s. 1. 68 × 1023 J 1. 68 × 1047 J 1. 68 × 10–21 J 1. 68 × 10–45 J.

Answer 1

The energy of the IR photon is $\rm 1.68\;\times\;10^{-21}$ J. Thus, option C is correct.

The energy of the radiations propagating in the air with the velocity of $\rm 3\;\times\;10^8$ m/s is given by:

$E=h\nu$

Where, h is Planck's constant, and $\nu$ is the frequency.

Computation for the energy of IR photon

The value of Planck's constant is given as, $\rm 6.63\;\times\;10^{-34}\;J.s^-^1$

The frequency of the IR radiation is $\rm 2.53\;\times\;10^1^2\;Hz$

Substitute the values for the energy of the photon

$\rm E=6.63\;\times\;10^{-34}\;J.s^{-1}\;\times\;2.53\;\times\;10^{12}\;Hz\\ E=16.8\;\times\;10^{-22}\;J\\E=1.68\;\times\;10^{-21}\;J$

The energy of the IR photon is $\rm 1.68\;\times\;10^{-21}$ J. Thus, option C is correct.

Learn more about the energy of photons, here:
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