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Vera_Pavlovna [14]
3 years ago
14

Types of atoms. The basic unit of matter. Pure substance is what?

Chemistry
2 answers:
ivanzaharov [21]3 years ago
7 0

Solids, liquids, gases, and plasma are all matter. When all atoms that make up a substance are the same, then that substance is an element. Elements made of only one kind of atom. Because of this, elements are called "pure" substances.

hope this helps :)

Serhud [2]3 years ago
4 0

A pure substance is a substance that doesnt have any additional ions added to it

For example, in bottled water there are Magnesium ions in it along with others. This is NOT PURE WATER

Also pure substances can be retrieved using separating techniques

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3 years ago
Which type of chemical bond involves the exchange of electrons
Alex17521 [72]

Answer:

Ionic or Electrovalent Bonding

Explanation:

There are primarily two categories of bonding between chemical entities. We have; Ionic Bonding and Covalent Bonding.

Ionic bonding or electrovalent bonding is the complete transfer of valence electron(s) between atoms. There is the transfer of electron from typically a metal to a non metal.

Covalent Bonding however involves the sharing of electrons between atoms. Depending on whuch atoms provide the electrons, it can be ordinary covalent oor coordinate covelent bond.

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3 years ago
The taste of drinking water can be improved by removing impurities from our municipal water by adding substances to the water th
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3 years ago
What does the chemical formula CaCI2 show about the compound or represents?
atroni [7]

Answer:

Two elements because Can is one element and Cl is another. The two is a coeficient that states how many of that element there is.

I hope this helps you!!!

8 0
3 years ago
If you have 120. mL of a 0.100 M TES buffer at pH 7.55 and you add 3.00 mL of 1.00 M HCl, what will be the new pH? (The pKa of T
Simora [160]

Answer:

The new pH after adding HCl is 7.07

Explanation:

The formula for calculating pH of a buffer is

pH = pKa + log([Conjugate base]/[Acid])

<u>Before adding HCl,</u>

         7.55 = 7.55 + log([Conjugate base]/[Acid])

⇔      log([Conjugate base]/[Acid])  = 0

⇔     [Conjugate base] = [Acid] = 1/2 x 0.100 = 0.05 M

⇒ Mole of Conjugate base = Mole of Acid = 0.05 M x 0.12 mL = 0.006 mol

<u>After adding HCl (3.00 mL, 1.00 M)</u>

⇒ Mole of HCl = 0.003 x 1 = 0.003 mol)

New volume solution is 120 m L+ 3 mL = 123 mL

HCl is a strong acid, it will convert the conjugate base to acid form, or we can express

Mole of new Conjugate base = 0.006 - 0.003 = 0.003 mol

                ⇒ Concentration = 0.003/0.123 M

Mole of new Acid form = 0.006 + 0.003 = 0.009 mol

                ⇒ Concentration = 0.009/0.123 M

Use the formula

pH = pKa + log([Conjugate base]/[Acid])

    = 7.55 + log(0.003 / 0.009) = 7.07

8 0
3 years ago
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