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VikaD [51]
2 years ago
6

How many milliliters of an injection containing 250 mg of aminophylline in each 10 ml should be used in filling a medication ord

er calling for 15 mg of aminophylline?
Chemistry
1 answer:
Serhud [2]2 years ago
7 0

0.6 milliliters

Let the injection contain X mL of solution.

Then,

An injection containing 250 mg of aminophylline per 10 mL  =  15 mg of aminophylline / X mL of an injection

250 mg / 10 mL = 15 mg / X mL

250 X = 150

X = 15/25

X = 0.6 mL

So, when filling a prescription that calls for 15 mg of aminophylline,

0.6 milliliters of an injection with 250 mg of aminophylline in every 10 ml should be used.

➤ A sterile, nonpyrogenic solution of aminophylline in water is known as aminophylline injection, USP. Anhydrous theophylline weighs about 79% as much as aminophylline (dihydrate). Aminophylline Injection is injected slowly into the vein, or it can be diluted and infused slowly into the vein.

What is the purpose of aminophylline injection?

Aminophylline is used to treat breathing issues that could be brought on by:

  • Asthma
  • Emphysema
  • Bronchitis and other ailments.

Aminophylline works by helping to open up your airways, allowing more air into your lungs.

Find more on aminophylline at : brainly.com/question/13251991

#SPJ4

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0.47dm³

Explanation

Given parameters :

Molarity of NaCl = 6.67M

Number of moles = 3.12mol

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Volume of NaCl = number of moles/Molarity

Volume of NaCl = 3.12mol/6.67M

Volume of NaCl = 0.47dm³

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3 years ago
A student wants to make a 0.600 M aqueous solution of barium sulfate, BaSO4, and has a bottle containing 12.00 g of barium sulfa
love history [14]

<u>Answer: </u>The volume of the solution is 85.7 mL

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}} .....(1)

We are given:

Molarity of solution = 0.600 M

Given mass of BaSO_4 = 12.00 g

We know, molar mass of BaSO_4=[(1\times 137.33)+(1\times 32.07)+(4\times 16)]=233.4g/mol

Putting values in equation 1, we get:

0.600=\frac{12.00\times 1000}{233.4\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{12.00\times 1000}{233.4\times 0.600}=85.68mL=85.7mL

The rule of significant number that is applied for the problems having multiplication and division:

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.

Hence, the volume of the solution is 85.7 mL

5 0
2 years ago
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