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snow_tiger [21]
2 years ago
12

If 9x^2-6x+5 is rewritten as p^2-2p+5, what is p in terms of x

Mathematics
1 answer:
Crazy boy [7]2 years ago
6 0

Answer:

p = 3x

Step-by-step explanation:

p² = 9x² = 3² *x²

p² = (3x)²

p = 3x

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erastovalidia [21]
No, it does not represent a function
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3 years ago
Difference of the square of (x+6)(x+4)
sweet-ann [11.9K]

Answer:

x^2 + 10x + 24

Step-by-step explanation:

(x+6)(x+4)

x^2 + 4x + 6x + 24

x^2 + 10x + 24

5 0
3 years ago
Which of the following situations represents choosing a random sample? Assign each person of the population a number. Put all th
Nina [5.8K]
Answer: The first and second options are random samples.

First, assign numbers and drawing the number from a bowl would be a great way to get a random sample. Everyone has the same chance of being selected.

Second, using an alphabetical order is just like the first choice. The chances are the same for everyone.

However, in the third choice, you won't get a random sample. You will get an old and young group. Not a random group of the population.
7 0
4 years ago
Jack will spend a total of exactly $15 on Redbix movies and games. What equation in standard form can he use to graoh a line sho
alina1380 [7]

Answer:

1.25x+2.5y -15 = 0

Step-by-step explanation:

Total amount to be spent on Redbix movies and games = $15

Money to be paid for each movie = $1.25

Money to be paid for each game = $2.50

To find:

Equation in standard form that can be used to graph the line.

Solution:

First of all, let us learn about the standard form of equation of a line.

Standard form can be represented as:

Ax+By+C =0

Where A,B, C are constants.

Now, let us try to make equation.

Let number of movies bought = x

Amount to be paid for movies = $1.25x

Let number of movies bought = y

Amount to be paid for movies = $2.50y

Total money is $15.

Therefore, we can write the equation as:

1.25x+2.5y = 15

Standard form can be written as:

1.25x+2.5y -15 = 0

4 0
3 years ago
On average 83.1% of welds performed by a particular welder are defective. if, in one day, the welder creates three welds. what i
Nuetrik [128]
Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.

Using the binomial distribution, we want all three to be defective.
P(X = 3) = \binom{3}{3}(p)^{3}{q}^{3 - 3}
P(X = 3) = \binom{3}{3}(0.831)^{3}(1)
P(X = 3) = (0.831)^{3} \approx 0.573856191
4 0
3 years ago
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