The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
Learn more about Tension calculations : brainly.com/question/24994188
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Answer:
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Explanation:
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As an object falls toward earth, the potential energy of the object: Decreases
<h3>What is the gravitational potential energy towards the earth?</h3>
In this case, the formula for the Potential energy is:
E = Em + Ek + Eg
Where;
Em is energy due to mass
Ek is kinetic energy
Eg is energy due to gravity
Thus, as the potential energy falls toward earth, Eg will approach 0, which will decrease its amount.
Read more about gravitational potential energy at; brainly.com/question/26590030
