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Ostrovityanka [42]
3 years ago
15

Name the law that applies to a driver while driving in the rightmost lane in the pictures?.

SAT
1 answer:
kotykmax [81]3 years ago
7 0

There re a lot of laws. The law that applies to a driver while driving in the rightmost lane in the pictures attached is the move over law.

<h3>What is the Move Over Law?</h3>

This is known to be a law that  requires you to Move Over a lane. Here,  one can safely do so due to the fact that they have stopped law enforcement, emergency, sanitation, etc.

A Move Over law is a also known as a law which requires any motorists to move over and change lanes so as to get a safe clearance to law enforcement officers, firefighters, etc.

Learn more about Law from

brainly.com/question/26264191

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What is the molar solubility of agcl (ksp = 1. 80 × 10⁻¹⁰) in 0. 500 m nh₃? (kf of ag(nh₃)₂⁺ is 1. 7 × 10⁷)
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Based on the calculations, the molar solubility of AgCl in 0. 500 M of NH₃ is equal to 2.77 × 10⁻² M.

<u>Given the following data:</u>

  • Ksp of mg(oh)₂ = 1.8 × 10⁻¹⁰
  • Concentration of NH₃ = 0.500
  • Kf of ag(nh₃)₂⁺ = 1.7 × 10⁷

<h3>How to determine the molar solubility.</h3>

First of al, we would write the properly balanced chemical equation for this chemical reaction:

                          AgCl(s)\rightleftharpoons Ag^{+} (aq)+ Cl^{-}(aq)       Ksp = 1.8 × 10⁻¹⁰

                AgCl(s) + 2NH_3(aq)\rightleftharpoons  Ag(NH_3)_2^{+}(aq)   Kf = 1. 7 × 10⁷

K = Ksp × Kf

K = 1. 80 × 10⁻¹⁰ × 1.7 × 10⁷

K = 3.06 × 10⁻³

Mathematically, the Ksp for the above chemical reaction is given by:

K=\frac{ [Ag(NH_3)_2^{+}][Cl]}{[NH_3]^2}\\\\3.06 \times 10^{-3}=\frac{[x][x]}{0.50^{2 }}\\\\3.06 \times 10^{-3}=\frac{x^2}{0.25}\\\\x^2 = 7.65\times 10^{-4}\\\\x=\sqrt{7.65\times 10^{-4}}

x = 2.77 × 10⁻² M.

Read more on solubility here: brainly.com/question/3006391

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"May" can be location name of birth.

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