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2 years ago

5(4 + 6) - 72 and explain the answer thank you

Mathematics

2 answers:

Fittoniya [83]2 years ago

6 0

Answer:

5(4+6)-72
5x10-72
50-72
-22

Step-by-step explanation:

If you use PEMDAS, the P is for parenthesis.
So first, you do the (4+6) and then multiply it by 5, when you get that answer, do the final step. Subtract 72.

Hope this helped!! <3

Iteru [2.4K]2 years ago

4 0

Answer:

-22

Step-by-step explanation:

5(4+6)-72

5(10)-72

50-72

-22

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HELP RIGHT AWAY!!!PLEASE EXPLAIN HOW TO SOLVE THE PROBLEM

kumpel [21]

Answer:

264

Step-by-step explanation:

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1/2 (8x6) = 24

24 x 11 = 264 yd^3

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3 years ago

You are challenged to a lucky draw game. If you draw a face card (K, Q, J) from a standard deck of cards, you earn 10 points. If

Aleksandr [31]

The Expected value of a draw from the given question is; A; 0.77

We are told the face cards are K, Q, J. This means that there are 3 face cards for each of the 4 suits.

Since you earn 10 points for each face card, it means that;

total possible gain = 10 × 3 × 4 = 120

In a deck of cards, there are a total of 52 cards.

This means that;

Number of cards that are not K, Q or J = 52 - (4 × 3) = 40

Since 2 points are lost for drawing any of this 40 cards, then;

Total possible loss = 40 × 2 = 80

Expected gain = 120 - 80

Expected gain = 40

Expected value of a draw = 40/52

Expected value of a draw = 0.77

Read more about expected value at; brainly.com/question/1450915

4 0

2 years ago

Using the scale 1/2 inch = 100 miles, figure out the number

Wittaler [7]

Answer:

50 miles

Step-by-step explanation:

Multiply the given scale numbers by 1/2 to find your answer:

1/2 in = 100 mi

(1/2)(1/2 in) = (1/2)(100 mi) . . . . multiply the ratio values by 1/2

1/4 in = 50 mi

5 0

2 years ago

How do you decide if a decimal is a rational number?

Bogdan [553]

You decide if it has a pattern if it is a repeating pattern then it is a rational number decimal however if it a decimal with no pattern it is irrational

6 0

3 years ago

Luda [366]

Answer:

a) H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

b) $\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

c) $\chi^2_{crit}=5.991$

d) Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

High school Some College Bachelor or higher Total

Public Broadcasting 15 15 10 40

Commercial stations 5 25 10 40

Total 20 40 20 80

We need to conduct a chi square test in order to check the following hypothesis:

Part a

H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

The level os significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part b

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{20*40}{80}=10$

$E_{2} =\frac{40*40}{80}=20$

$E_{3} =\frac{20*40}{80}=10$

$E_{4} =\frac{20*40}{80}=10$

$E_{5} =\frac{40*40}{80}=20$

$E_{6} =\frac{20*40}{80}=10$

And the expected values are given by:

High school Some College Bachelor or higher Total

Public Broadcasting 10 20 10 40

Commercial stations 10 10 20 40

Total 20 30 30 80

Part b

And now we can calculate the statistic:

$\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(2-1)(3-1)=2$

Part c

In order to find the critical value we need to look on the right tail of the chi square distribution with 2 degrees of freedom a value that accumulates 0.05 of the area. And this value is $\chi^2_{crit}=5.991$

Part d

And we can calculate the p value given by:

$p_v = P(\chi^2_{3} >33.75)=2.23x10^{-7}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(33.75,2,TRUE)"

Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

7 0

3 years ago

5(4 + 6) - 72 and explain the answer thank you ​

5(4 + 6) - 72 and explain the answer thank you