Answer:
- 8/25 = 32/100
- 7/20 = 35/100
Step-by-step explanation:
25 and 20 have a least common multiple of 100, so that is your least common denominator.
8/25 = (8·4)/(25·4) = 32/100
7/20 = (7·5)/(20·5) = 35/100
Answer:
1
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
2
+
5
−
2
=
0
x^{2}+5x-2=0
x2+5x−2=0
=
1
a={\color{#c92786}{1}}
a=1
=
5
b={\color{#e8710a}{5}}
b=5
=
−
2
c={\color{#129eaf}{-2}}
c=−2
=
−
5
±
5
2
−
4
⋅
1
(
−
2
)
√
2
⋅
1
Step-by-step explanation:
this should help
Answer:
P = 2x + 150
Step-by-step explanation:
P = 2x + 150
Hey there
__________
The correct answer is
Whatever each CD costs, what each person paid is that cost times the number of CDs purchased (no sales tax for this problem).
So, the price of one CD is a factor of $66 (a number of $ that divides $66 evenly).
In theory, it could be $1, $2, $3, $6, $11, $22, $66.
It could even be $0.50, $0.25, $0.20, $0.10, $0.05,...
Also, the price of one CD must be a factor of $54. such as $54,$27,$18,$9,$6,$3,$2,$1,... .
You are looking for the most that price could be.
The grew greatest price that is in both lists is $6.
How can you make those lists?
You can start with the total price, then the price divided by 2, by 3, by whatever whole number you can divide it.
Otherwise, you could find the greatest common factor of 66 and 54
from the prime factorization of both numbers.
___________________
Hope this helps you
Answer:
Choice C is the answer.
Known information:
a = adult $
s = student $
We have 2 adults and 3 students.
Step-by-step explanation:
To find the total price of tickets given a # of students and adults, multiply a by the # of adults and multiply s by the # of students. Therefore, it would look like this:
2a + 3s = price
Therefore, choice C is the answer.
Hope this helps!
