Resistor 1 and three are in series so the total resistance is 1.
Answer:
The minimum uncertainty in the velocity is 232.57 m/s.
Explanation:
Given that,
Location of a particle with uncertainty = 0.13 nm
Mass of particle ![m=1,745\times10^{-27}\ kg](https://tex.z-dn.net/?f=m%3D1%2C745%5Ctimes10%5E%7B-27%7D%5C%20kg)
We need to calculate the minimum uncertainty in the velocity
Using heisenberg's uncertainty principle,
![\Delta x\cdot \Delta p\geq \dfrac{h}{4\pi}](https://tex.z-dn.net/?f=%5CDelta%20x%5Ccdot%20%5CDelta%20p%5Cgeq%20%5Cdfrac%7Bh%7D%7B4%5Cpi%7D)
![\Delta x\cdot m\Delta v \geq \dfrac{h}{4\pi}](https://tex.z-dn.net/?f=%5CDelta%20x%5Ccdot%20m%5CDelta%20v%20%5Cgeq%20%5Cdfrac%7Bh%7D%7B4%5Cpi%7D)
![\Delta v=\dfrac{h}{4\pi\times m\Delta x}](https://tex.z-dn.net/?f=%5CDelta%20v%3D%5Cdfrac%7Bh%7D%7B4%5Cpi%5Ctimes%20m%5CDelta%20x%7D)
Put the value into the formula
![\Delta v=\dfrac{6.63\times10^{-34}}{4\pi\times 1.745\times10^{-27}\times0.13\times10^{-9}}](https://tex.z-dn.net/?f=%5CDelta%20v%3D%5Cdfrac%7B6.63%5Ctimes10%5E%7B-34%7D%7D%7B4%5Cpi%5Ctimes%201.745%5Ctimes10%5E%7B-27%7D%5Ctimes0.13%5Ctimes10%5E%7B-9%7D%7D)
![\Delta v= 232.57\ m/s](https://tex.z-dn.net/?f=%5CDelta%20v%3D%20232.57%5C%20m%2Fs)
Hence, The minimum uncertainty in the velocity is 232.57 m/s.
Answer:
A: The acceleration is 7.7 m/s up the inclined plane.
B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane
Explanation:
Let us work with variables and set
![m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.](https://tex.z-dn.net/?f=m%3D5kg%5C%5C%5C%5CF_H%3D100N%5C%5C%5C%5C%5Cmu%3D0.3%5C%5C%5C%5C%5Ctheta%3D37%5Eo.)
As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.
Part A:
From the free body diagram we see that the total force along the x-axis is:
![F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).](https://tex.z-dn.net/?f=F_%7Btot%7D%3Dmg%2Asin%28%5Ctheta%29%2BF_s-F_Hcos%28%5Ctheta%29.)
Now the force of friction is
where
is the normal force and from the diagram it is ![F_y=mg*cos(\theta).](https://tex.z-dn.net/?f=F_y%3Dmg%2Acos%28%5Ctheta%29.)
Thus
Therefore,
![F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).](https://tex.z-dn.net/?f=F_%7Btot%7D%3Dmg%2Asin%28%5Ctheta%29%2B%5Cmu%2Amg%2Acos%28%5Ctheta%29-F_Hcos%28%5Ctheta%29%5C%5C%5C%5C%3Dmg%28sin%28%5Ctheta%29%2B%5Cmu%2Acos%28%5Ctheta%29%29-F_Hcos%28%5Ctheta%29.)
Substituting the value for
we get:
![F_{tot}= -38.63N.](https://tex.z-dn.net/?f=F_%7Btot%7D%3D%20-38.63N.)
Now acceleration is simply
![a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BF_H%7D%7Bm%7D%20%3D%5Cfrac%7B-38.63N%7D%7B5kg%7D%20%3D-7.7m%2Fs.)
The negative sign indicates that the acceleration is directed up the incline.
Part B:
![d=\frac{1}{2} at^2](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B1%7D%7B2%7D%20at%5E2)
Which can be rearranged to solve for t:
![t=\sqrt{\frac{2d}{a} }](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B%5Cfrac%7B2d%7D%7Ba%7D%20%7D)
Substitute the value of
and
and we get:
which is our answer.
Notice that in using the formula to calculate time we used the positive value of
, because for this formula absolute value is needed.
An investigation that has been done by more than one scientist with similar findings has been replicated.
<h3>What does replication in science mean?</h3>
The expression 'replication in science' makes reference to the same experimental result through different hypothesis testing procedures, which is fundamental to reinforcing a scientific idea.
In conclusion, an investigation that has been done by more than one scientist with similar findings has been replicated.
Learn more about replication in science here:
brainly.com/question/24382552
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Answer:
C: time of contact is increased
Explanation:
When a ball is falling from height, it maintains the same mass but velocity may change depending on the conditions in that environment.
Now, to catch the ball on your palm, you need to find a way to reduce the momentum of the ball upon hitting your hand.
Now, to reduce the momentum, we need to apply impulse.
This is because we know that;
Impulse(I) = F × t = change in momentum (m(v - u))
Thus;
I = Ft
F = I/t
We are told that extending the hand reduces the force of contact on your hand.
Thus;
For F which is the force to be reduced, the denominator (t) has to be increased.
Thus, the correct answer is that time of contact is increased