Answer:
540C.
Explanation:
A capacitor of capacitance C when charged to a voltage of V will have a charge Q given as follows;
Q = CV ----------(i)
From the question, the initial charge on the capacitor is the charge on it before it was connected to the resistor. In other words, the initial charge on the capacitor will have a maximum value which can be calculated using equation (i) above.
Where;
C = 6F
V = 90V
Substitute these values into equation (i) as follows;
Q = 6 x 90
Q = 540 C
Therefore, the initial charge on the capacitor is 540C.
Answer:
B)a tool to drop temperatures, mercury, an electric current, and a tool to measure resistance
... I can’t see the attached assignment that you put on here.
Answer: pick A moves 10.2 metre
Explanation: since they were given a quick push simultaneously the product of their distance moved and velocity would be equal.
Let the distance moved by puck B x then that of puck A would be 18-x.
So therefore we have that,
1.3*(18-x) = 1.7*x
23.4 - 1.3x = 1.7x
23.4=3x
Making x subject of formula we have
x = 23.4/3 = 7.8m
But the distance moved by puck A is 18-x. So therefore,
18-7.8=10.2meter
