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Vladimir79 [104]
3 years ago
6

No pressure but anyone who can answer these is a genius. (Please fill in the question mark)

Chemistry
1 answer:
disa [49]3 years ago
4 0

use variable

1K₂MnF₆ + aSbF₅⇒ bKSbF₆ + cMnF₃ + dF₂

K, left=2,right=b⇒b=2

Mn, left=1, right=c⇒c=1

Sb, left=a, right=b⇒a=b=2

F, left=6.1+5a, right=6b+3c+2d

equation:

6+5(2) = 6(2)+3(1)+2d

16=15+2d

1=2d

d=0.5

So the reaction equation becomes:

1K₂MnF₆ + 2SbF₅⇒ 2KSbF₆ + 1MnF₃ + 0.5F₂ x2

2K₂MnF₆ + 4SbF₅⇒ 4KSbF₆ + 2MnF₃ + F₂

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You have cyclohexene, water, cyclohexanol, and a little sulfuric acid catalyst in a test tube at 60 oC and everything is at equi
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Answer:

See explanation

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8 0
3 years ago
A single hydrogen atom has a mass of 1.67 × 10−24 g. A sodium atom has an atomic mass of 23. How many sodium atoms are required
statuscvo [17]
<h3>Answer:</h3>

                      2.55 × 10²² Na Atoms

<h3>Solution:</h3>

Data Given:

                 M.Mass of Na  =   23 g.mol⁻¹

                 Mass of Na  =  973 mg  =  0.973 g

                 # of Na Atoms  =  ??

Step 1: Calculate Moles of Na as:

               Moles  =  Mass ÷ M.Mass

               Moles  =  0.973 g ÷ 23 g.mol⁻¹

               Moles  =  0.0423 mol

Step 2: Calculate No, of Na Atoms as:

As 1 mole of sodium atoms counts 6.022 × 10²³ and equals exactly to the mass of 23 g. So, we can write,

               Moles  =  No. of Na Atoms ÷ 6.022 × 10²³ Na Atoms.mol⁻¹

Solving for No. of Na Atoms,

               No. of Na Atoms  =   Moles × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =   0.0423 mol × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =  2.55 × 10²² Na Atoms

<h3>Conclusion: </h3>

                          2.55 × 10²² sodium atoms are required to reach a total mass of 973 mg in a substance of pure sodium.


5 0
3 years ago
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