16 g/ml
<h3>Further explanation</h3>
Given
mass = 32.40 g
volume = 2.0mL
Required
Density
Solution
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
Density formula:
ρ = density
m = mass
v = volume
Input the value :
ρ = 32.40 g / 2.0 ml
ρ = 16.2 g/ml
Rules for division: The least number of significant figures in the problem determines the number of significant figures in the answer.
32.40 = 4 sig.fig
2.0 = 2 sig fig
The answer must be 2 sig fig
So the answer = 16 g/ml
Answer:
- second choice:<em><u> 1.0 g of the solution contains 15 × 10⁻⁶ g of benzene.</u></em>
Explanation:
ppm is a unit of concentration that means parts per million. In grams that is grams of solute per one million (10⁶) grams of solution.
Then, <em>15 ppm of benzene</em> means that there are 15 grams of benzen in 1,000,000 grams of solution.
That leads to:
- 1,000,000 g solution / 15 g benzene
Multiplying numerator and denominator by 10⁻⁶ you find:
- 1,000,000 × 10⁻⁶ g solution / (15 × 10⁻⁶ g benzene)
Simplifying:
- 1.0 g solution / (15 × 10⁻⁶ g benzene)
Which is read as 1.0 g of the solution contains 15 × 10⁻⁶ g of benzene, i.e. the second answer choice.
Answer:
N₂O₅
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 7.546 g
Mass of nitrogen (N) = 1.957 g
Empirical formula =?
Next, we shall determine the mass of oxygen present in the compound. This can be obtained as follow:
Mass of compound = 7.546 g
Mass of nitrogen (N) = 1.957 g
Mass of Oxygen (O) =?
Mass of O = (Mass of compound) – (Mass of N)
Mass of O = 7.546 – 1.957
Mass of O = 5.589 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of nitrogen (N) = 1.957 g
Mass of oxygen (O) = 5.589 g
Divide by their molar mass
N = 1.957 / 14 = 0.14
O = 5.589 / 16 = 0.35
Divide by the smallest
N = 0.140 / 0.14 = 1
O = 0.35 / 0.14 = 2.5
Multiply through by 2 to express in whole number
N = 1 × 2 = 2
O = 2.5 × 2 = 5
The empirical formula of the compound is N₂O₅.
Answer:
CH₄ + N₂Cl₄ → CCl₄ + N₂ + 2H₂
Explanation:
Chemical equation:
CH₄ + N₂Cl₄ → CCl₄ + N₂ + H₂
Balance chemical equation:
CH₄ + N₂Cl₄ → CCl₄ + N₂ + 2H₂
Step one:
CH₄ + N₂Cl₄ → CCl₄ + N₂ + H₂
Left hand side Right hand side
C = 1 C = 1
H = 4 H = 2
Cl = 4 Cl = 4
N = 2 N = 2
Step 2:
CH₄ + N₂Cl₄ → CCl₄ + N₂ + 2H₂
Left hand side Right hand side
C = 1 C = 1
H = 4 H = 4
Cl = 4 Cl = 4
N = 2 N = 2
