Answer:
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Therefore the length of a side of a cube is ![\sqrt[3]{64}\ or\ 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%5C%20or%5C%204)
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Step-by-step explanation:
The volume of a cube is expressed as L³ where L is the length of each side of the cube.
Given volume of a cube = 64in³
On substituting;
64 = L³
Taking the cube root of both sides to determine L we have;
![\sqrt[3]{64} = (\sqrt[3]{L})^{3}\\\sqrt[3]{64} = L\\L=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%20%28%5Csqrt%5B3%5D%7BL%7D%29%5E%7B3%7D%5C%5C%5Csqrt%5B3%5D%7B64%7D%20%3D%20L%5C%5CL%3D4)
Therefore the length of a side of a cube is ![\sqrt[3]{64}\ or\ 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%5C%20or%5C%204)
Answer:
Step-by-step explanation:
(-5) * (-3) * (-3) = -5 * -3 * -3 = 15 * -3 = -45
Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.