<span>d.2HNO3 (aq) + Sr(OH)2 (aq) → 2H2O (l) + Sr(NO3)2(aq)
4H </span>4H
8O 8O
2N 2N
1Sr 1Sr<span>
</span>
It would be 5.0 more in i did this
Sucrose; C12H22O11
C9H8O4; acetyl salicylic acid
H2O2; hydrogen peroxide,
NaOH; sodium hydroxideExplanation:
Your answer is going to be b
The answer is (3) HClO. In the Cl2, chlorine has an oxidation number of zero. In HCl, the oxidation number is -1. In HClO2, the oxidation number is +3. In HClO, it is +1. You can calculate this by using O with oxidation number of -2 and H with +1.