Answer:
42672 kJ
Explanation:
Chemical reaction:
C₂H₄ + H₂ → C₂H₆ + heat
Now we calculate the number of moles of ethane C₂H₆:
number of moles = mass / molecular weight
number of moles of ethane = 10.1 / 30 = 0.336 kmoles = 336 moles
And determine the heat released:
if 127 kJ are released when 1 mole of C₂H₆ is produced
then X kJ are released when 336 moles of C₂H₆ is produced
X = (127 × 336) / 1 = 42672 kJ
Answer:
41.66 mL of 12.0 M sulfuric acid are needed.
Explanation:
Concentration of sulfuric acid solution taken =
Volume of the 12.0 M Solution = 
Concentration of required solution = 
Volume of required 1.00 M solution = 
(Dilution)
41.66 mL of 12.0 M sulfuric acid are needed.
The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.
Answer:
"Gases and particles in Earth's atmosphere scatter sunlight in all directions. Blue light is scattered more than other colors because it travels as shorter, smaller waves. This is why we see a blue sky most of the time."
it would need to gain 2 more for it to achieve a stable configuration
the best way to remember this is the noble gasses all have 8 valence electrons and that they are the most stable elements on the periodic table
In the periodic table the lanthanoid and the actinides are place separately at the bottom because of their electronic configuration and their properties compared to the other elements.
The the lanthanoid and the actinides are place separately at the bottom in the periodic table due to their electronic configuration and the properties. and to make the periodic table more convenient . if we place the f block elements that is he lanthanoid and the actinides then the size of the periodic table will increase. the f block elements are called as the inner transition element.
Thus , to make the periodic table more convenient and to group the elements in the block the the lanthanoid and the actinides are place separately at the bottom.
To learn more about lanthanoid and actinide here
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