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blondinia [14]
2 years ago
14

The diagonals of a rhombus are 24 cm, 32 cm. Its perimeter is

Mathematics
1 answer:
Marysya12 [62]2 years ago
7 0

Answer:

80cm

Step-by-step explanation:

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At what values of x does the graph of f(x)= sin x intersect the x-axis?
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Which value of a makes the equation 5a+1 1/2=4 true?
ss7ja [257]

Answer:

5a+1 1/2=4

a = 1/2

Step-by-step explanation:

4 0
2 years ago
after hitting the black friday sales, sarah bought her dress on sale for $35. She saved 45%, what was the original cost.
8090 [49]

The original cost of the dress is $63.64

Step-by-step explanation:

After hitting the black Friday sales

  • Sarah bought her dress on sale for $35
  • She saved 45%

We need to find the original cost of the dress

The money that Sarah saved is the value of the discount on the dress

Assume that the price of the dress before the black Friday is 100%

∵ The price of the dress before the black Friday is 100%

∵ She saved 45% when she bought it the black Friday

∴ The price of the dress is decreased by 45%

∵ She bought the dress for $35 ⇒ (after discount)

Let use use the percentage method

→ Before discount  :  Discount  :  After discount

→        100%              :       45%     :      55% (100 - 45)

→         x                    :                    :      35

By using cross multiplication

∵ x × 55% = 35 × 100%

- Divide both sides by 55%

∴ x = 63.64

The original cost of the dress is $63.64

Learn more:

You can learn more about percentage in brainly.com/question/12501490

#LearnwithBrainly

3 0
3 years ago
HELP ASAP I WILL GIVE BRAINLIEST!!
Alexxx [7]

Consider the function F(x)= x³ +½x² −2x +3. Use calc and algebra to find any and all stationary points on the graph of the function.Precalc need help ASAP

Solution:

the above function has more than one root or more than one solution. The derivative of the function represents the slope of the tangent line to the curve

F(x)= x³ +½x² −2x +3, F'(x) = 3(x3-1)+(1/2)(2)(x2-1)-2(x1-1)+0

F'(x)=3x2+x-2 is the slope of the tangent line

setting the slope =0 and solving the quadratic equations, you find all the

critical points of interest

3x2+x-2=0, solve by factoring (3x-2)(x+1)=0, then 3x-2=0, x= 2/3

and x+1=0, x=-1 substituting these values of x in the original equation

you get the corresponding values of F(x) such that;

F(x)= x³ +½x² −2x +3, F(x)=(2/3)3+1/2(2/3)2-2(2/3)+3

= 8/27+4/18-4/3+3 = 8/27+2/9-4/3+3/1 = 59/27 and the first point is

(2/3, 59/27)

F(x)= x³ +½x² −2x +3, F(x)=(-1)3+1/2(-1)2-2(-1)+3

= -1+1/2+2+3 = 9/2 and the 2nd point is ( -1, 9/2)

these two points represents points where the slope of the tangent line to the curve is 0 and could be either maximum or minimum points

You can also find the y intercepts where x = 0 F(x)= x³ +½x² −2x +3, setting x = 0, y= F(x)=3 and the point ( 0,3) is a y intercept setting y = 0, then x intercepts can be found upon solving the equation x³ +½x² −2x +3 =0

3 0
2 years ago
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