Wavelength- <span>distance between successive crests of a wave.
frequency- t</span><span>he rate at which something occurs or is repeated over time.
amplitude-</span><span> maximum extent of a vibration.</span>
Answer:
1500 m/s
Explanation:
Recall that for a wave,
Speed = frequency x wavelength
here we are given frequency = 500 Hz and wavelength = 3m
simply substitute into above equation
Speed = 500 Hz x 3m
= 1500 m/s
Answer:

Explanation:
We know,
..............(1)
where,
η = Efficiency of the engine
T₁ = Initial Temperature
T₂ = Final Temperature
Q₁ = Heat available initially
Q₂ = Heat after reaching the temperature T₂
Given:
η =0.280
T₁ = 3.50×10² °C = 350°C = 350+273 = 623K
Q₁ = 3.78 × 10³ J
Substituting the values in the equation (1) we get

or

or

⇒ 
Now,
The entropy change (
) is given as:

or

substituting the values in the above equation we get


If the runner is running in a circular track then yes when something or someone is moving in a circular motion at a constant speed they are indeed accelerating. They’re accelerating because the direction of the velocity vector is changing
Answer:
<h2>the ans...is dc circuit...</h2>