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maxonik [38]
2 years ago
10

Answer it or not your choice

Physics
1 answer:
Zigmanuir [339]2 years ago
3 0

Answer:

Explanation:

(a) 0 to 90

(b) 90 to 180

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Describe how air resistance would affect a falling object ​
aivan3 [116]

Answer:

With air resistance, acceleration throughout a fall gets less than gravity (g) because air resistance affects the movement of the falling object by slowing it down. How much it slows the object down depends on the surface area of the object and its speed

Explanation:

PLZ MARK AS THE BRAINLIEST

HAVE A GOOD DAY

: )

4 0
3 years ago
Superman is off to visit Lois lane. He sees he's late and increases his flying speed. I know he defies the laws of physics anywa
mario62 [17]

Answer:

975 m/s^2

Explanation:

The formula for rate of acceleration is

(Final velocity - intial velocity)/ time taken

If you plug in your data you will get 975 m/s^2

(1600 m/s -1210 m/s )/.4 s = 975 m^2

7 0
3 years ago
A bar-magnet with magnetic moment 2.5 Am^2 is placed in a homogeneous magnetic field (of 0.1 T that is directed along the z-axis
Angelina_Jolie [31]

Answer:

1)

Force on bar magnet  = 0

Torque on bar magnet = 0

2)

Force on bar magnet  = 0

Torque on bar magnet = 0.177 Nm

3)

Force on bar magnet  = 0

Torque on bar magnet = 0.25 Nm

Explanation:

Part 1)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

\tau = MBsin\theta

when bar magnet is inclined along z axis along magnetic field

then we will have

\tau = MBsin0 = 0

Part 2)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

\tau = MBsin\theta

when bar magnet is pointing 45 degree with z axis then we will have

\tau = MBsin45

\tau = (2.5)(0.1)sin45

\tau = 0.177 Nm

Part 3)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

\tau = MBsin\theta

when bar magnet is pointing 90 degree with z axis then we will have

\tau = MBsin90

\tau = (2.5)(0.1)sin90

\tau = 0.25 Nm

8 0
4 years ago
What velocity must a 1210 kg car have in order to have the same momentum as the pickup truck in the sample problem
harina [27]

Answer:

P=mv 2250*25=56250

Explanation:

p of truck =2250*25 =56250

since p of truck = p of car

then p of car = 56250

therefore p of car = 1210 * v

or, 56520=1210v

or,v= 56520/1210=46.48

so, v of car is 46.48m/s

3 0
3 years ago
The strength of the electric field at a certain distance from a point charge is represented by E. What is the strength of the el
Nana76 [90]

Answer:

E

Explanation:

Using Coulomb's law equation

Force of the charge = k qQ /d²

and E = F/ q

substitute for F

E = ( K Qq/ d² ) / q

q cancel q

E = KQ / d²

so twice  the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²

7 0
4 years ago
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