1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fofino [41]
3 years ago
13

What is the unique geological feature found on Mercury surface?

Physics
1 answer:
Cloud [144]3 years ago
3 0

Answer:

The surface of Mercury has landforms that indicate its crust may have contracted. They are long, sinuous cliffs called lobate scarps. These scarps appear to be the surface expression of thrust faults, where the crust is broken along an inclined plane and pushed upward.

Explanation:

I hope this helps a little bit.

You might be interested in
Which factor is a component of skill-related fitness?
lukranit [14]
There are six skill-related fitness components: agility, balance, coordination<span>, </span>speed<span>, power, and reaction time. Skilled athletes typically excel in all six areas. Agility is the ability to change and control the direction and position of the body while maintaining a constant, rapid motion.</span>
6 0
3 years ago
Read 2 more answers
11. When an object is speeding up in the positive direction, what vs happering to its
Alina [70]

Answer:

im pretty sure its b

Note that when the acceleration is negative — on the interval [0, 2) — that means that the velocity is decreasing. When the acceleration is positive — on the interval (2, 4] — the velocity is increasing. Speeding up and slowing down.

4 0
3 years ago
Topics:
spin [16.1K]

I need you to make me an invented poem written please not in image

3 0
2 years ago
A tow truck is pulling a car out of a ditch by means of a steel cable (y = 2.0 x 1011 n/m2) that is 9.55 m long and has a radius
Anna11 [10]
If you know the real modulus of the cable (Y), the length, and the area (based on the radius), you can compute the spring constant, k = AE/L. Then, if you know the force used, you can compute the displacement, using F = kd, or d = F / k = FL/(AE). Our answer should work out to units of length. So, 
d = 803 N * 9.06 m / [pi*(0.574 cm)^2 * 2.0 x 10^11 N/m^2] 
d = 3.5 x 10^-8 Nm^3 / (cm^2 * N) 
d = 3.5 x 10^-8 m^3 / cm^2 * (100 cm / 1 m)^2 
d = 3.5 x 10^-4 m
4 0
3 years ago
Physical science!!!!!!helpppp
ipn [44]

Answer:

Option B

10.36 m/s

Explanation:

Using the first given equation, then velocity=distance/time

Since distance is provided as 200 m and time, t is 19.3 seconds then substituting these figures yields

v=200/19.3=10.3626943

Rounding off to 2 decimal places, then

v=10.36 m/s

6 0
3 years ago
Other questions:
  • Choose the option below that best completes this sentence: when two circuit elements (e.g., light bulbs, resistors, etc.) are in
    7·1 answer
  • a 0.230 kg baseball is thrown with a velocity of 35 m/s. The ball hits the catcher's mitt with a force of 150 N, how long does i
    9·1 answer
  • A bullet of mass 3.7 g strikes a ballistic pendulum of mass 4.6 kg. The center of mass of the pendulum rises a vertical distance
    14·1 answer
  • If a displacement vector has a negative x component and a positive y component,
    7·1 answer
  • Calculate the time required (in years) for water to penetrate a layer of clay that is 40 cm deep when exposed to a hydraulic gra
    7·2 answers
  • I really need help this was due Friday! I will mark brainiest!
    12·1 answer
  • The major intracellular positively charged electrolyte is
    9·1 answer
  • A bicyclist at the top of a hit begins to coast without pedaling. The bicycle speeds up as it descends to the bottom of the hill
    9·1 answer
  • The trunk of a elephant may extend up to 2.2 m. It acts much like an organ pipe only open at one end when the elephant blows air
    15·1 answer
  • A 235 kg object and a 1.37×1012 kg are located 2.59×104 m away from each other. What is the force due to gravity between the two
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!