Answer:
The autoionization of water is:
2H₂O ⇄ H₃O⁺ + OH⁻ Kw
Explanation
2 moles of water can generate hydronium and hydroxide, when they work as an acid or as a base
If we take account that the concentration of protons (hydroniums), at the standard temperature is 1×10⁻⁷ M, it can be considered that the molarity of water is a constant that can be incorporated into a “greater” constant that also includes to Kc and that is known as ionic product of water, Kw. The expression is:
Kw = [H₃O⁺] . [OH⁻] / [H₂O]²
We do not include water → Kw = [H₃O⁺] . [OH⁻]
Since the water dissociation reaction produces the same concentration of H₃O⁺ as OH⁻, [OH⁻] in pure water will also be 1×10⁻⁷ M
Kw = 1×10⁻⁷ . 1×10⁻⁷ = 1×10⁻¹⁴
pKw = pH + pOH
14 = 7 + 7
Answer:
Mass = 47.04 g
Volume = 23.94 L
Solution:
The equation for given reaction is as follow,
BaCO₃ + 2 HNO₃ → Ba(NO₃)₂ + CO₂ + H₂O
According to this equation,
197.34 g (1 mole) BaCO₃ produces = 44 g (1 mole) of CO₂
So,
211 g of BaCO₃ will produce = X g of CO₂
Solving for X,
X = (211 g × 44 g) ÷ 197.34 g
X = 47.04 g of CO₂
As we know,
44 g (1 mole) CO₂ at STP occupies = 22.4 L volume
So,
47.04 g of CO₂ will occupy = X L of Volume
Solving for X,
X = (47.04 g × 22.4 L) ÷ 44 g
X = 23.94 L Volume
Called a(n) convection current
The particles in a solid have an orderly, fixed arrangement.
