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olga2289 [7]
2 years ago
11

An example of a transverse wave is A. light B. sound C. matter D. none of the above

Physics
2 answers:
Amanda [17]2 years ago
8 0

Answer:

y=2x+b-4 with equals an intercept to end up with the answer if you move 5 feet north at 465 degrees run

guajiro [1.7K]2 years ago
3 0

Answer:

A light

Explanation:

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The half-life of plutonium 239 is 24,200 years. Assume that the decay rate is proportional to the amount. Determine the amount o
kotykmax [81]

Answer:

time taken is equal to 14,156 years

Explanation:

we know,

Y=Ae^{-kt}

at t = 0

Y(0) = A

given that half life of plutonium 239 = 24,200

\dfrac{A}{2}=Ae^{-kt}\\0.5=e^{-kt}\\k\times 24200 = ln(2)\\k = \dfrac{ ln(2)}{24200}

Y=Ae^{-kt}

\frac{3}{2} = e^{-kt}\\ln(1.5)=-\dfrac{ ln(2)}{24200}\times t\\t=-\dfrac{ln(1.5)\times 24200}{ ln(2)}\\t=14,156 \ years

hence time taken is equal to 14,156 years

5 0
3 years ago
A 2 kg toy cart and a 6 kg toy cart have a spring compressed between them. When the spring expands, it sends the 2 kg toy cart o
harkovskaia [24]

Answer:

The speed of second toy cart is 4 m/s.

(c) is correct option

Explanation:

Given that,

Mass of first toy cart = 2 kg

Mass of second toy cart = 6 kg

Speed of first toy cart = 12 m/s

We need to calculate the speed of second toy cart

Using formula of momentum

m_{1}v_{1}=m_{2}v_{2}

Where, m₁ = mass of first toy cart

m₂ = mass of second toy cart

v₁ = velocity of first toy cart

v₂ =  velocity of second toy cart

Put the value into th formula

2\times12=6\times v_{2}

v_{2}=\dfrac{2\times12}{6}

v_{2}=4\ m/s

Hence, The speed of second toy cart is 4 m/s.

(c) is correct option

4 0
4 years ago
When you jump upward, your hang time is the time your feet are off the ground. Does hang time depend on the vertical component o
hjlf

Answer:

It only depends on the vertical component

Explanation:

Hello!

The horizontal component will tell you how much you travel in that direction.

You could have a large horizontal velocity, but if the vertical velocity is zero, you will never be out of the ground. Similarly, you could have a zero horizontal velocity, but if you have a non-zero vertical velocity you will be some time off the ground. This time can be calculated by two means, one is using the equation of motion (position as a function of time) and the other using the velocity as a fucntion of time.

For the former you must find the time when the position is zero.

Lets consider the origin of teh coordinate system at your feet

y(t) = vt - (1/2)gt^2

We are looking for a time t' for which y(t')=0

0 = vt' - (1/2)gt'^2

vt' = (1/2)gt'^2

The trivial solution is when t'=0 which is the initial position, however we are looking for t'≠0, therefore we can divide teh last equation by t'

v = (1/2)gt'

Solving for t'

t' = (2v/g)

7 0
4 years ago
What is current of 12 ohm? help me pleasee​
Ne4ueva [31]

Answer:

Current for 12 ohms = 2.5

Explanation:

Ohm's Law:

Voltage = IR

Current = V/R

Resistance = V/I

Therefore, current = 30V/12 Ohms

30/12 = 2.5

So current for 12 ohms = 2.5

I hope this helps :>

4 0
2 years ago
What is the potential engery of a 150 kg diver standing on a diving board that is 10m high?
krek1111 [17]
The Answer Is Going To Be14,700
5 0
3 years ago
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