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2 years ago

Identify the percent of change as an increase or a decrease.

Mathematics

2 answers:

icang [17]2 years ago

6 0

$50-\frac{35}{50}$

$→ \frac{15}{50}$

$→ \frac{3}{10}$

$→ 30\%$

Answer :- $30\%$ decrease

icang [17]2 years ago

3 0

Answer:

30% decrease

Step-by-step explanation:

50 - 35 / 50

= 15/50

= 3/10

= 30% (decrease as value is lower than original)

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Maggie has 3 quarters, Elizabeth has 5 quarters, and Johnny has 7 quarters. If q represents $0.25, which of the following expres

miskamm [114]

Answer:

3 + 5 + 7 = 15

they have 15 quarters altogether so answer is 15q

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3 years ago

At the city Museum child admission is $6.40 in adult admission is $9.70 on Sunday 149 tickets were sold for a total sales of $11

Law Incorporation [45]

Answer:

Adult=58

Step-by-step explanation:

c=child, a=adult

6.4c+9.7a=1145 equation 1

c+a=149 equation 2

a=149-c modified equation 2 to isolate a

6.4c+9.7(149-c)=1145 substitute value of a from equation 1 into equation 2

6.4c+1445.3-9.7c=1145

-3.3c=-300.3

c=91

solve for a

c+a=149

91+a=149

a=58

Check answer:

6.4c+9.7a=1145

6.4(91)+9.7(58)=1145

582.40+562.60=1145

1145=1145

8 0

3 years ago

Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu

kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

$f(x) = {x}^{5} - {x}^{3} + 6$

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

$f'(x) = 5 {x}^{4} - 3 {x}^{2}$

At turning point f'(x)=0.

$5 {x}^{4} - 3 {x}^{2} = 0$

This implies that,

${x}^{2} (5 {x}^{2} - 3) = 0$

${x}^{2} = 0 \: or \: 5 {x}^{2} - 3 = 0$

$x = - \frac{ \sqrt{15} }{5} \: or \: x = 0 \: \: or \: x =\frac{ \sqrt{15} }{5}$

We plug this values into the original function to obtain the y-values of the turning points

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$

We now use the second derivative test to determine the absolute maximum minimum on the interval [-1,1]

$f''(x) = 20 {x}^{3} - 6x$

$f''( - \frac{ \sqrt{15} }{5} ) \: < \: 0$

Hence

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} + 750))$

is a maximum point.

$f''( \frac{ \sqrt{15} }{5} ) \: > \: 0$

Hence

$( \frac{ \sqrt{15} }{5} , \frac{1}{125} (- 6 \sqrt{15} + 750))$

is a minimum point.

$f''(0) \: =\: 0$

Hence (0,-6) is a point of inflexion

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3 years ago

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Combine the like terms, which would give you -y-1

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3 years ago

Find the product of 1 3/5 and 8 (show work please tysm)

Virty [35]

Answer:

20 4/5

Step-by-step explanation

13/5 x 8/1 = 104/5= 20 4/5

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4 years ago