Answer:
given mass =1500kg
intial velocity(u)=0 m/s
final velocity(v)=20m/s
time(s)=10 sec
accelerating force of the car engine=final velocity-intial velocity/time=20-0/10=20/10=2m/s^2
After first stop the number of passengers is :52 -y +4second stop: (52 -y +4) - (52 -y +4) * (1/3) + 4 = 25
so we have to solve : (52 -y +4) - (52 -y +4) * (1/3) + 4 = 25 at the second stop there was (52 -y +4) passengersand you have been told that 1/3 of them get offso we have to subtract (52 -y +4) * (1/3)
80% is 128 of the number 160 For example: 128/160 = 80%
7abc and 8abc-8 are the answers.