Answer:
63 books in each boxes
1 book left which need a box
Step-by-step explanation:
James has 568 books
He plans to put them into 9 boxes
Therefore the number of books n each boxes can be calculated as follows
= 568/9
63 remainder 1
Hence there would be 63 books in each boxes and 1 book would be left which need another box
Answer:
I don't know sooooooooop
mark me as brainliest ok understood
Answer:
Q1: 12.5
Q3: 16
IQR: 3.5
Step-by-step explanation:
Mean : 14.25
Median : 13.5
Mode : 13, 12
Range: 6
Minimum :12
Maximum: 18
Count n: 8
Sum: 114
Quartiles Quartiles:
Q1 --> 12.5
Q2 --> 13.5
Q3 --> 16
Interquartile
Range IQR: 3.5
Outliers: none
Turn each number into the product of it's prime factors.
32=16x2=2x2x2x2x2=2^5
48=24*2=6x4x2=2x3x2x2x2
Pick the highest number that occurs. In this case it is 2. Now we have to see how many times it appears in both. It appears 5 times in 32 and 4 times in 48. 4 is the highest number of times it appears in the numbers so:
2^4=2x2x2x2=16
The Greatest Common Factor (GCF) of 32 and 48 is 16.
