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ExtremeBDS [4]
3 years ago
9

What is the gravitational potential energy of a 0.1 kg apple sitting on top of a 12.5 m flagpole? Note: GPE= mgh. m= mass, g= ac

celeration due to gravity (9.8 m/s^2),
h= objects height above the ground.
Physics
1 answer:
Pachacha [2.7K]3 years ago
6 0
<span>GPE= mgh = 0.1 kg * 9.8 m/s^2  * 12.5m = 12.25 J</span>
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Answer:

1 second later the vehicle's velocity will be:

v(1)= 6\,\,\frac{m}{s} \\

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v(5)=14\,\,\frac{m}{s}

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Recall the formula for the velocity of an object under constant accelerated motion (with acceleration "a"):

v(t)=v_0+a\,t

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so we can estimate the velocity of the vehicle at different times just by replacing the requested "t" in the expression:

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