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ExtremeBDS [4]
3 years ago
9

What is the gravitational potential energy of a 0.1 kg apple sitting on top of a 12.5 m flagpole? Note: GPE= mgh. m= mass, g= ac

celeration due to gravity (9.8 m/s^2),
h= objects height above the ground.
Physics
1 answer:
Pachacha [2.7K]3 years ago
6 0
<span>GPE= mgh = 0.1 kg * 9.8 m/s^2  * 12.5m = 12.25 J</span>
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Hope this help you!!

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Since there will be no potential energy when the ball is on the ground, the change in potential energy is equal to the potential energy at the start when the ball is 19.6m above the ground.

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