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2 years ago

I need help!!! I just need the answer for p and i also need the answer step by step!!

Mathematics

1 answer:

klasskru [66]2 years ago

8 0

Answer:

x = 18

m = 21.2

p = 31.8

Step-by-step explanation:

The ratio of the left-side length to the bottom-side length is the same for both triangles:

x/11.2 = (x +27)/28

28x = 11.2(x +27) = 11.2x +302.4 . . . . . multiply by 11.2·28

16.8x = 302.4 . . . . . . . subtract 11.2x

x = 18 . . . . . . . . . . . . divide by 16.8

The length of m can be found using the Pythagorean theorem. The sum of the squares of the legs is the square of the hypotenuse.

x^2 +11.2^2 = m^2

m = √(324 +125.44) = √449.44 = 21.2

The length of p can also be found using the Pythagorean theorem. We prefer the proportion ...

p/27 = m/x

p = 27(21.2/18) = 31.8

The lengths of the unknown sides in the figure are ...

x = 18

m = 21.2

p = 31.8

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Answer:

A: 2x+1= -1/4x+3

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3 years ago

Suppose in the population, the Anger-Out score for men is two points higher than it is for women. The population variances for m

tatuchka [14]

Answer:

a)= 2

b) 6.324

c) P= 0.1217

Step-by-step explanation:

a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)

b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by

σ_X`1- X`2 = √σ²/n1 +σ²/n2

Var ( X`1- X`2) = Var X`1 + Var X`2 = σ²/n1 +σ²/n2

σ_X`1- X`2 =√20 +20 = 6.324

if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.

Where as Z is normally distributed with mean zero and unit variance.

If we take X`1- X`2= 0 and u1-u2= 2 and standard deviation of the sampling distribution = 6.324 then

Z= 0-2/ 6.342= -0.31625

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8 0

2 years ago

Suppose that the time (in hours) required to repair a machine is an exponentially distributed random variable with mean 1/0.41/0

lbvjy [14]

Answer:

a) P(t>3)=0.30

b) P(t>10|t>9)=0.67

Step-by-step explanation:

We have a repair time modeled as an exponentially random variable, with mean 1/0.4=2.5 hours.

The parameter λ of the exponential distribution is the inverse of the mean, so its λ=0.4 h^-1.

The probabity that a repair time exceeds k hours can be written as:

$P(t>k)=e^{-\lambda t }=e^{-0.4t}$

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$P(t>3)=e^{-0.4*3}=e^{-1.2}= 0.30$

(b) the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours?

The exponential distribution has a memoryless property, in which the probabilities of future events are not dependant of past events.

In this case, the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours is equal to the probability that a repair takes at least (10-9)=1 hour.

$P(t>10|t>9)=P(t>1)$

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6 0

3 years ago

The volume of a rectangular prism is 2x^3+9x^2-8x-36 with height x + 2. Using synthetic division, what is the area of the base?

navik [9.2K]

Answer:

Area of the base = $2x^2+5x-18$

Step-by-step explanation:

We know that volume of rectangular prism = (Area of base) x (Height)

or [Area of base] = [Volume]/[Height]

So basically we need to divide given area by given height to find the answer.

given height is (x+2) that means (x+2) must be factor of volume equation

or x=-2 must be root of volume equation so write down coefficients of volume equation then we divide by -2 as shown in attached picture.

Last digit on the right is always remainder.

Remaining coefficients {2, 5, -18} will give the area equation: $2x^2+5x-18$

Hence final answer is:

Area of the base = $2x^2+5x-18$

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3 years ago

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sdas [7]

From the given data we shall obtain the following boxplot, which we can generate the information given:

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1st Qu=6.425
3rd Qu=7.650

</span>

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3 years ago

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