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oksian1 [2.3K]
3 years ago
11

Before a star is born, the matter that will become the star exists as a

Physics
2 answers:
vazorg [7]3 years ago
6 0

Answer:

The answer is D

Explanation:

I'm too lz to explain everything.

sorry.

zloy xaker [14]3 years ago
3 0

Answer:

The answer is D) cool, dark nebula

Explanation:

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What is the meaning of inversely proportion​
-BARSIC- [3]
If two variables are inversely proportional, then when one increases, the other decreases, and vice versa. If a variable, y, is inversely proportional to a variable, x, then y = k/x, where k is the proportionality constant.
4 0
2 years ago
Read 2 more answers
A 7382 N piano is to be pushed up a(n) 2.16 m frictionless plank that makes an angle of 22.7 ◦ with the horizontal. Calculate th
lubasha [3.4K]

Answer:

Work done, W = 6153.31 Joules

Explanation:

It is given that,

Weight of piano, W = F = 7382 N

It is pushed 2.16 meters friction less plank

The angle with horizontal, \theta=22.7^{\circ}

When the piano slide up plank at a slow constant rate. The y component of force is taken into consideration. The net force acting on it is given by :

F_y=F\ sin\theta

Work done is given by :

W=F_y\times d

W=F\ sin\theta \times d

W=7382 sin(22.7) \times 2.16

W = 6153.31 Joules

So, the work done in sliding the piano up the plank is 6153.31 Joules. Hence, this is the required solution.

7 0
3 years ago
For a cosine function with amplitude A=0.75 and period T=10, what is y(4)?
mixer [17]
 <span>2π/T = 2π/10 = π/5 

y(x) = A sin (wx) = 0.75 sin (πx/5) 

y(4) = 0.75 sin (4π/5) = 0.4408389392... ≈ 0.441</span><span>
</span>
8 0
3 years ago
Read 2 more answers
If you doubled the load resistor in a Wheatstone bridge, the load current would not be half as much. Why not?
Fofino [41]
Doubling the size of a load resistor increases the load current. Increasing the load resistance, in turn the total circuit resistance is reduced. The load current would not be half as much since when you increase the size of load resistor then load current increases.
6 0
3 years ago
A 56.0 kg bungee jumper jumps off a bridge and undergoes simple harmonic motion. If the period of oscillation is 11.2 s, what is
andre [41]

Answer:

2.80N/m

Explanation:

Given data

mass m= 56kg

perios T= 11.2s

The expression for the period is given as

T=2π√m/k

Substitute

11.2= 2*3.142*√56/k

square both sides

11.2^2= 2*3.142*56/k

125.44= 351.904/k

k=351.904/125.44

k= 2.80N/m

Hence the spring constant is 2.80N/m

8 0
3 years ago
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