Answer:
the intensity will be 4 times that of the earth.
Explanation:
let us assume the following:
intensity of light on earth =J
distance of earth from sun = d
intensity of light on other planet = K
distance of other planet from sun =
(from the question, the planet is half as far from the sun as earth)
from the question the intensity is inversely proportional to the square of the distance, hence
- intensity on earth : J =

J
= 1 ... equation 1
- intensity on other planet : K =
(the planet is half as far from the sun as earth)
K
= 1 ....equation 2
- equating both equation 1 and 2 we have
J
= K
J
= K
J = 
K = 4J
intensity of light on other planet (K) = 4 times intensity of light on earth (J)
Answer:
B) 12.1 m/s
Explanation:
Sum of the forces in the y direction:
∑F = ma
N − mg = 0
N = mg
Sum of the forces in the radial direction:
∑F = ma
F = m v² / r
Nμ = m v² / r
Substituting and solving for v:
mgμ = m v² / r
gμ = v² / r
v = √(gμr)
Given that μ = 0.200 and r = 75.0 m:
v = √(9.81 m/s² × 0.200 × 75.0 m)
v = 12.1 m/s
Answer:
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Explanation:
Answer:
The speed of the baseball is approximately 19.855 m/s
Explanation:
From the question, we have;
The frequency of the microwave beam emitted by the speed gun, f = 2.41 × 10¹⁰ Hz
The change in the frequency of the returning wave, Δf = +3190 Hz higher
The Doppler shift for the microwave frequency emitted by the speed gun which is then reflected back to the gun by the moving baseball is given by 2 shifts as follows;


Where;
Δf = The change in frequency observed, known as the beat frequency = 3190 Hz
= The speed of the baseball
c = The speed of light = 3.0 × 10⁸ m/s
f = The frequency of the microwave beam = 2.41 × 10¹⁰ Hz
By plugging in the values, we have;


The speed of the baseball,
≈ 19.855 m/s